Question

我的应用程序包含EditText的某些实例。我必须清理所有EditText 单击按钮。我需要写一个条件来清理所有EditText 其中EditText个为空。我将如何做？

public class Fragment1 extends Fragment implements View.OnClickListener
{
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState)
    {
        View v=inflater.inflate(R.layout.fragment1,null);
        seekBar1 = v.findViewById(R.id.fragment1SeekBar1);
        seekBar2 = v.findViewById(R.id.fragment1SeekBar2);
        seekBar3=v.findViewById(R.id.fragment1SeekBar3);

        edTxt1=v.findViewById(R.id.fragment1EditText1);
        edTxt2=v.findViewById(R.id.fragment1EditText2);
        edTxt3=v.findViewById(R.id.fragment1EditText3);

        fragment1button1=v.findViewById(R.id.fragment1Button1);
        fragment1button1.setOnClickListener(this);}

    @Override
    public void onClick(View view){
        int val1 = Integer.parseInt( edTxt1.getText().toString());
        int val2=Integer.parseInt( edTxt2.getText().toString());
        int val3=Integer.parseInt( edTxt3.getText().toString());

        switch(view.getId()){
            case R.id.fragment1Button1:
                if(edTxt1.equals("")){
                    edTxt1.getText().clear();
                    edTxt2.getText().clear();
                    edTxt3.getText().clear();
                }else if(edTxt2.equals("")){
                    edTxt1.getText().clear();
                    edTxt2.getText().clear();
                    edTxt3.getText().clear();}
                else if (edTxt3.equals("")){
                    edTxt1.getText().clear();
                    edTxt2.getText().clear();
                    edTxt3.getText().clear();}
                break;}
}
}

Answer 1

if(edTxt1.equals(""))

您的条件不正确。他们应该看起来像这样：

if(edTxt1.getText().toString().equals(""))

Answer 2

如果要将编辑文本的文本设置为null：

edTxt1.setText("");

否则，您可以将其设置为不可见而消失。

edTxt1.setVisibility(View.INVISIBLE);

Answer 3

如果要将“ EditText”设置为空，请使用

if(edTxt1.getText().toString().equals("")) {
    edTxt1.setText("");
    edTxt2.setText("");
    edTxt3.setText("");
} else if(edTxt2.getText().toString().equals("")) {
    edTxt1.setText("");
    edTxt2.setText("");
    edTxt3.setText("");
} else if (edTxt3.getText().toString().equals("")) {
    edTxt1.setText("");
    edTxt2.setText("");
    edTxt3.setText("");
}
break;

或者如果您想删除edittext

if (edTxt1.getText().toString().equals("")) {
    edTxt1.setVisibility(View.GONE);
    edTxt2.setVisibility(View.GONE);
    edTxt3.setVisibility(View.GONE);
} else if(edTxt2.getText().toString().equals("")) {
    edTxt1.setVisibility(View.GONE);
    edTxt2.setVisibility(View.GONE);
    edTxt3.setVisibility(View.GONE);
} else if (edTxt3.getText().toString().equals("")) {
    edTxt1.setVisibility(View.GONE);
    edTxt2.setVisibility(View.GONE);
    edTxt3.setVisibility(View.GONE);
}
break;

Answer 4

尝试这种方式

  switch(view.getId())

{
    case R.id.fragment1Button1:
        if (TextUtils.isEmpty(edTxt1.getText().toString())) {
            edTxt1.getText().clear();
            edTxt2.getText().clear();
            edTxt3.getText().clear();
        } else if (TextUtils.isEmpty(edTxt2.getText().toString())) {
            edTxt1.getText().clear();
            edTxt2.getText().clear();
            edTxt3.getText().clear();
        } else if (TextUtils.isEmpty(edTxt3.getText().toString())) {
            edTxt1.getText().clear();
            edTxt2.getText().clear();
            edTxt3.getText().clear();
        }
        break;
}

Answer 5

每EditText都这样做

if (!edTx.getText().toString().equals("")) {
    edTx.setText("");
}

Answer 6

尝试一下如果条件改变

 if(edTxt1.equals(""))

到

 if(edTxt1.getText().toString().length()>0)

让我知道是否可行

如何清除某些EditText？

6 个答案: