Question

在DB2中，有一种基本的说法：

当sku（从table1中选择*，其中tb1field ='SMOMD'）时为'True'结束

好的，这是我到目前为止的查询，我已经进行了至少一个月的时间，所以任何帮助都会很棒。

select tb4.customer, tb4.sku, tb4.qty, tb4.retqty, tb4.stipqty, tb4.lastdate, tb4.firstdate, tb4.stipdate

from(
--Table 4
select tb3.Customer as Customer, tb3.sku as SKU, tb3.qty as Qty, tb3.retqty as RetQty, tb3.stipqty as STIPQty,
case when tb3.lastdate is null then '00/0000' else substr(tb3.lastdate,5,2)||'/'||substr(tb3.lastdate,1,4) end as LastDate,
case when tb3.firstdate is null then '00/0000' else substr(tb3.firstdate,5,2)||'/'||substr(tb3.firstdate,1,4) end as FirstDate,
case when tb3.stipdate is null then '00/0000' else substr(tb3.stipdate,5,2)||'/'||substr(tb3.stipdate,1,4) end as STIPDate

from(
--Table 3
select tb2.Customer as Customer, tb2.SKU as SKU, tb2.Qty as Qty, tb2.RetQty as RetQty, tb2.STIPQty as STIPQty,
max(case when tb2.TranID in ('010','100') then tb2.datenum end) as LastDate,
min(case when tb2.TranID in ('010','100') then tb2.datenum end) as FirstDate,
case when tb2.RC = '4M' then tb2.datenum end as STIPDate

from(
--Table 2
select tb1.Customer as Customer, tb1.SKU as SKU,
sum(case when tb1.TranID in ('010','100') then abs(tb1.OrdNet) else '0' end) as Qty,
sum(case when tb1.TranID = '500' and tb1.rc != '4M' then abs(tb1.OrdNet) else '0' end) as RetQty,
count(case when tb1.rc = '4M' then tb1.sku end) as STIPQty,
tb1.datenum as datenum, tb1.TranID as tranid, tb1.RC as rc

from(
--Table 1
select distinct stkund as Customer, sthptg||space(1)||stmodl||space(1)||stvari||space(1)||stfarb||space(1)||stgroe as SKU, 
stvorg as TranID, stggru as RC, stprg09 as PG9, stprg08 as PG8, stperi as datenum, ormne1 as OrdNet
from st_usus.s_stati_pv
join caspdtau.cospf440 on stadrn = jadr40
where trim(stvert) in ('111S','122S')
and sthptg != 'V'
and aktv40 = 'A'
and stprg01 in ('01','04')
and stprg02 = '01'
and stvorg in ('500','010','100')
and stperi >= '20160100'

) as tb1
group by tb1.Customer, tb1.SKU, tb1.datenum, tb1.tranid, tb1.rc


) as tb2
group by tb2.customer, tb2.sku, tb2.qty, tb2.retqty, tb2.stipqty, tb2.tranid, tb2.rc, tb2.datenum

) as tb3
group by tb3.customer, tb3.sku, tb3.qty, tb3.retqty, tb3.stipqty, tb3.lastdate, tb3.firstdate, tb3.stipdate

) as tb4
order by tb4.Customer, tb4.sku

Answer 1

我不会试图完全解读您要做什么...

一些一般性建议，而不是使用嵌套表表达式（NTE）

select <..> from (select <...>from mytable)

考虑通用表表达式（CTE）

with 
  table1 as (select <...> from st_usus.s_stati_pv join caspdtau.cospf440 on stadrn = jadr40)
, table2 as (select <...> from table1)
, table3 as (select <...> from table2)
, table4 as (select <....> from table3)
select <...> from table4;

每个CTE（即tableX）可以根据需要引用先前的CTE或物理表/视图。最终选择可以引用一个或多个CTE，以及一个或多个物理表或视图。

关于使用CTE进行构建的妙处在于，您可以在每个步骤之后检查结果。

with 
  table1 as (select <...> from st_usus.s_stati_pv join caspdtau.cospf440 on stadrn = jadr40)
select * from table1;

有什么方法可以在IBM DB2环境中完成此操作

1 个答案: