Question

有人可以帮助我解决此问题，为什么它返回此错误：对象是不可迭代的。

def leap_year(start_year, end_year):
    for start_year in end_year:
        # Leap Year Check
        if start_year % 4 == 0 and start_year % 100 != 0:
            print(start_year, "is a Leap Year")
        elif start_year % 100 == 0:
            print(start_year, "is not a Leap Year")
        elif start_year % 400 ==0:
            print(start_year, "is a Leap Year")
        else:
            print(start_year, "is not a Leap Year")
        if end_year % 4 == 0 and end_year % 100 != 0:
            print(end_year, "is a Leap Year")
        elif end_year % 100 == 0:
            print(end_year, "is not a Leap Year")
        elif end_year % 400 ==0:
            print(end_year, "is a Leap Year")
        else:
            print(end_year, "is not a Leap Year")

leap_year(2000, 2006)

Answer 1

您输入的end_year是2006，这是一个不可迭代的数字。

如果要遍历end_year，则需要将其设为

即for start_year in end_year

要使end_year变得可迭代，您可以尝试range(end_year)

即for start_year in range(end_year)

将留给您查找范围功能

对象是不可迭代的。我如何使此代码起作用

1 个答案: