Question

所以我正在制作一个电子邮件验证系统，但urlsafe_base64_decode返回的是None而不是pk。

def post(self, request):
    form = self.form_class(request.POST)

    if form.is_valid():

        user = form.save(commit=False)

        username = form.cleaned_data['username']
        password = form.cleaned_data['password']

        subject = 'Activá tu mail'
        current_site = get_current_site(request)
        encoded_uid = urlsafe_base64_encode(force_bytes(user.pk)).decode()
        message = render_to_string('firstpage/acc_active_email.html', {
            'user': user,
            'domain': current_site.domain,
            'uid': encoded_uid,
            'token': account_activation_token.make_token(user),
            })
        to_email = form.cleaned_data['email']
        from_email = 'backend_email@gmail.com'
        send_mail(subject, message, from_email, [to_email])

        user.set_password(password)

        user.save()
        user_profile=UserProfile.objects.create(user=user)
        #returns user objects if credentials are correct
        user = authenticate(username=username, password=password)

        if user is not None:

            if user.is_active:
                login(request, user)
                return redirect('/')

    return render(request, self.template_name, {'form': form})

然后用户单击链接，并将其重定向到此功能

def activate(request, uidb64=None, token=None):
    uid = urlsafe_base64_decode(uidb64).decode()
    user = User.objects.get(pk=uid)
    if user is not None and account_activation_token.check_token(user, token):
        user.is_active = True
        user.save()
        login(request, user)
        # return redirect('home')
        return HttpResponse('Thank you for your email confirmation. Now you can login your account.')
    else:
        print(user)
        print(uid)
        print(account_activation_token.check_token(user, token))
        return HttpResponse('Activation link is invalid!')

uidb64返回与urlsafe_base64_encode（force_bytes（user.pk））。decode（）相同，但urlsafe_base64_decode（uidb64）.decode（）返回None。

我正在使用Django 2.1。

Answer 1

您需要使用force_text返回代表任意对象的str对象并保留惰性对象，请使用-force_text(urlsafe_base64_decode(uidb64)) 有关更多参考，请访问文档

-https://docs.djangoproject.com/en/2.1/ref/utils/#django.utils.encoding.force_text

希望这会对您有所帮助。

Django urlsafe_base64_decode返回None

1 个答案: