在添加到购物车后，WooCommerce以模式获取产品ID（产品页面上带有ajax）

Question

我在单个产品页面上将ajax用于“添加到购物车”按钮，效果很好。在成功的ajax请求中，它会打开模式，我试图获取所添加产品的ID，并希望在模式中显示一些信息，但是我无法传递ID，我也尝试了全局变量和其他一些方法。

这是我的代码：

add_action('wp_ajax_woocommerce_ajax_add_to_cart', 'woocommerce_ajax_add_to_cart');
add_action('wp_ajax_nopriv_woocommerce_ajax_add_to_cart', 'woocommerce_ajax_add_to_cart');

function woocommerce_ajax_add_to_cart() {

    $product_id = apply_filters('woocommerce_add_to_cart_product_id', absint($_POST['product_id']));
    $quantity = empty($_POST['quantity']) ? 1 : wc_stock_amount($_POST['quantity']);
    $variation_id = absint($_POST['variation_id']);
    $passed_validation = apply_filters('woocommerce_add_to_cart_validation', true, $product_id, $quantity);
    $product_status = get_post_status($product_id);

    if ($passed_validation && WC()->cart->add_to_cart($product_id, $quantity, $variation_id) && 'publish' === $product_status) {

        do_action('woocommerce_ajax_added_to_cart', $product_id);

        if ('yes' === get_option('woocommerce_cart_redirect_after_add')) {
            wc_add_to_cart_message(array($product_id => $quantity), true);
        }

        WC_AJAX :: get_refreshed_fragments();
    } else {

        $data = array(
            'error' => true,
            'product_url' => apply_filters('woocommerce_cart_redirect_after_error', get_permalink($product_id), $product_id));

        echo wp_send_json($data);
    }

    wp_die();
}

<script type="text/javascript">

(function ($) {

    jQuery(document).on('click', '.single_add_to_cart_button', function (e) {
        e.preventDefault();

        var $thisbutton = jQuery(this),
                $form = $thisbutton.closest('form.cart'),
                id = $thisbutton.val(),
                product_qty = $form.find('input[name=quantity]').val() || 1,
                product_id = $form.find('input[name=product_id]').val() || id,
                variation_id = $form.find('input[name=variation_id]').val() || 0;

        var data = {
            action: 'woocommerce_ajax_add_to_cart',
            product_id: product_id,
            product_sku: '',
            quantity: product_qty,
            variation_id: variation_id,
        };

        jQuery(document.body).trigger('adding_to_cart', [$thisbutton, data]);

        jQuery.ajax({
            type: 'post',
            url: wc_add_to_cart_params.ajax_url,
            data: data,
            beforeSend: function (response) {
                $thisbutton.removeClass('added').addClass('loading');
            },
            complete: function (response) {
                $thisbutton.addClass('added').removeClass('loading');
            },
            success: function (response) {

                if (response.error & response.product_url) {
                    window.location = response.product_url;
                    return;
                } else {
                    jQuery(document.body).trigger('added_to_cart', [response.fragments, response.cart_hash, $thisbutton]);
                }
                jQuery("#Modal").modal('show');
            },
        });

        return false;
    });
})(jQuery);

</script>

我想将ID传递给此模式

<!-- Modal -->
<div class="modal fade" id="Modal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel">
    <div class="modal-dialog" role="document">
        <div class="modal-content">
            <div class="modal-header">
                <?php echo $product_id; ?>
            </div>
            <div class="modal-body">
            </div>
            <div class="modal-footer"></div>
        </div>
    </div>
</div>

任何帮助将不胜感激，谢谢！