我有两组数据要合并并同时返回，但是我需要连接的列可能在集合A中有一个值，而在集合B中没有，反之亦然，所以LEFT / RIGHT JOIN并不理想。
设置A
查询-
SELECT o.organisation_id,
Count(call_opened) 'opened calls',
Format(call_opened, 'MMM-yy')'month name',
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_opened, 'MMM-yy'),
call_severity
返回-
organisation_id opened calls month name call_severity
BES 1 Apr-12 3
BES 1 Dec-13 3
BES 1 Jun-12 3
BES 1 Mar-12 3
BES 2 Nov-11 3
BES 1 Oct-11 3
设置B
查询-
SELECT o.organisation_id,
Count(call_closed) 'closed calls',
Format(call_closed, 'MMM-yy')'month name',
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_closed, 'MMM-yy'),
call_severity
返回-
organisation_id closed calls month name call_severity
BES 2 Aug-13 3
BES 1 Dec-11 3
BES 1 Dec-13 3
BES 1 Mar-12 3
BES 1 Nov-11 3
BES 1 Sep-12 3
到目前为止
查询-
SELECT opened.organisation_id,
Isnull(opened.[opened calls],0) 'opened calls',
Isnull(closed.[closed calls],0) 'closed calls',
opened.[month name],
opened.call_severity
FROM (SELECT o.organisation_id,
Count(call_opened) 'opened calls',
Format(call_opened, 'MMM-yy')'month name',
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_opened, 'MMM-yy'),
call_severity) opened
LEFT JOIN (SELECT o.organisation_id,
Count(call_closed) 'closed calls',
Format(call_closed, 'MMM-yy')'month name',
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_closed, 'MMM-yy'),
call_severity) closed
ON opened.organisation_id = closed.organisation_id
AND opened.[month name] = closed.[month name]
AND opened.call_severity = closed.call_severity
WHERE opened.Call_Severity <> 5
ORDER BY opened.organisation_id ASC
返回-
organisation_id opened calls closed calls month name call_severity
BES 1 0 Apr-12 3
BES 1 1 Dec-13 3
BES 1 0 Jun-12 3
BES 1 1 Mar-12 3
BES 2 1 Nov-11 3
BES 1 0 Oct-11 3
如您所见，由于集合B包含集合A中不存在的月份数据，因此这不会返回我需要的数据。
理想情况下，我希望这样返回数据-
organisation_id opened calls closed calls month name call_severity
BES 1 0 Apr-12 3
BES 1 1 Dec-13 3
BES 1 0 Jun-12 3
BES 1 1 Mar-12 3
BES 2 1 Nov-11 3
BES 1 0 Oct-11 3
BES 0 2 Aug-13 3
BES 0 1 Dec-11 3
BES 0 1 Sep-12 3
我考虑过要创建一个初始临时表，然后插入月份值并加入结果集，但是由于数据要回溯到2002年，所以这太麻烦了，太杂乱了，这是我可能或会做的我需要重做我的解决方案吗？
我认为这是调用表中需要的所有数据-
Call_ID Call_Opened Call_Closed Call_Severity User_id
28000001 2011-10-19 13:13:48.000 2011-11-09 11:47:03.000 3 825
28000002 2011-11-07 10:55:24.000 2012-03-05 08:27:54.000 3 825
28000003 2011-11-21 09:11:49.000 2011-12-19 08:41:36.000 3 825
28000006 2012-03-30 15:11:23.000 2013-08-29 15:51:39.000 3 825
28000007 2012-04-02 11:50:22.000 2013-08-29 15:52:11.000 3 825
28000008 2012-06-25 08:12:39.000 2012-09-28 16:32:08.000 3 825
28000012 2013-12-17 07:41:26.000 2013-12-17 08:58:35.000 3 825
答案 0 :(得分：2)
这是使用cross apply的好地方：
SELECT o.organisation_id,
SUM(v.is_open) as opened_calls,
SUM(v.is_close) as closed_calls,
Format(call_time, 'MMM-yy') as month_name,
call_severity
FROM call c JOIN
users u
ON u.user_id = c.user_id JOIN
organisation o
ON o.organisation_id = u.organisation_id CROSS APPLY
(VALUES (call_opened, 1, 0 ),
(call_closed, 0, 1)
) as v(call_time, is_open, is_close)
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_time, 'MMM-yy'),
call_severity
答案 1 :(得分：1)
您应使用UNION ALL进行公开通话/结束呼叫，然后在顶部查询中使用group。请参阅下面的样机。
让我知道您是否有任何问题。
SELECT organisation_id,
Isnull(SUM([opened calls]),0) 'opened calls',
Isnull(SUM([closed calls]),0) 'closed calls',
[month name],
call_severity
FROM (
---Set A
SELECT o.organisation_id,
Count(call_opened) 'opened calls',
0 'closed calls',
Format(call_opened, 'MMM-yy')'month name',
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_opened, 'MMM-yy'),
call_severity
UNION ALL ---Set B
SELECT o.organisation_id,
0 'opened calls',
Count(call_closed) 'closed calls',
Format(call_closed, 'MMM-yy')'month name',
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_closed, 'MMM-yy'),
call_severity
)S
GROUP BY
organisation_id,
[month name],
call_severity
答案 2 :(得分：0)
您必须使用工会
select organisation_id
, sum(opened_calls) opened_calls
, sum(closed_calls) closed_calls
, month_name
, call_severity
from (
SELECT o.organisation_id,
Count(call_opened) opened_calls,
0 closed_calls,
Format(call_opened, 'MMM-yy') month_name,
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_opened, 'MMM-yy'),
call_severity
union
SELECT o.organisation_id,
0 opened_calls
Count(call_closed) closed_calls,
Format(call_closed, 'MMM-yy') month_name,
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_closed, 'MMM-yy'),
call_severity
)tt
group by organisation_id, month_name, call_severity
答案 3 :(得分：0)
;WITH opened AS
(
SELECT o.organisation_id,
Count(call_opened) AS call_opened,
Format(call_opened, 'MMM-yy') AS month_name,
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_opened, 'MMM-yy'),
call_severity
),
closed AS
(
SELECT o.organisation_id,
Count(call_closed) AS call_closed,
Format(call_closed, 'MMM-yy') AS month_name,
call_severity
FROM call c
JOIN users u
ON u.user_id = c.user_id
JOIN organisation o
ON o.organisation_id = u.organisation_id
WHERE Call_Type = 'FT'
GROUP BY o.organisation_id,
Format(call_closed, 'MMM-yy'),
call_severity
)
SELECT COALESCE(opened.organisation_id, closed.organisation_id) AS organisation_id,
COALESCE(opened.call_opened, 0) AS call_opened, COALESCE(closed.call_closed, 0) AS call_closed,
COALESCE(opened.month_name, closed.month_name) AS month_name,
COALESCE(opened.call_severity, closed.call_severity) AS call_severity
FROM opened
FULL OUTER JOIN closed
ON opened.month_name = closed.month_name;