我想这更多是我的代码问题,而不是JSON.NET问题,但我不确定我要去哪里。
我下面有下面的类,该类用于序列化在此链接中找到的json数据:https://samples.openweathermap.org/data/2.5/weather?q=London,uk&appid=b6907d289e10d714a6e88b30761fae22
要构建此类,我使用了JSON到Google上的C#生成器。
下面也是我用来将JSON数据提取并序列化为WeatherData对象的方法。
private string GetJsonFromWeb(string resource, string city)
{
var request = new RestRequest(resource, Method.GET);
request.AddParameter("q", city);
request.AddParameter("APPID", "af5e6fd579e0ddb303afc1774487c77b");
var fullUrl = client.BuildUri(request);
Console.WriteLine("Full URL: " + fullUrl.AbsoluteUri);
var response = client.Execute(request);
string json = response.Content;
return json;
}
private WeatherData SerializeJsonToWeatherData(string json)
{
WeatherData weatherData = JsonConvert.DeserializeObject<WeatherData>(json);
return weatherData;
}
这些方法成功运行,因为可以稍后在应用程序中使用JSON数据在GUI中显示信息。但是,从API提取JSON后,JSON数据的MainData部分将设置为null。
class WeatherData
{
public Coord Coord { get; set; }
public List<Weather> Weather { get; set; }
public string Base { get; set; }
public MainData MainData { get; set; }
public int Visibility { get; set; }
public Wind Wind { get; set; }
public Clouds Clouds { get; set; }
public int Dt { get; set; }
public Sys Sys { get; set; }
public int Id { get; set; }
public string Name { get; set; }
public int Cod { get; set; }
}
public class Coord
{
public double Lon { get; set; }
public double Lat { get; set; }
}
public class Weather
{
public int Id { get; set; }
public string Main { get; set; }
public string Description { get; set; }
public string Icon { get; set; }
}
public class MainData
{
public double Temp { get; set; }
public int Pressure { get; set; }
public int Humidity { get; set; }
public double Temp_min { get; set; }
public double Temp_max { get; set; }
}
public class Wind
{
public double Speed { get; set; }
public int Deg { get; set; }
}
public class Clouds
{
public int All { get; set; }
}
public class Sys
{
public int Type { get; set; }
public int Id { get; set; }
public double Message { get; set; }
public string Country { get; set; }
public int Sunrise { get; set; }
public int Sunset { get; set; }
}
从上述API采样JSON
{
"coord": {
"lon": -0.13,
"lat": 51.51
},
"weather": [
{
"id": 300,
"main": "Drizzle",
"description": "light intensity drizzle",
"icon": "09d"
}
],
"base": "stations",
"main": {
"temp": 280.32,
"pressure": 1012,
"humidity": 81,
"temp_min": 279.15,
"temp_max": 281.15
},
"visibility": 10000,
"wind": {
"speed": 4.1,
"deg": 80
},
"clouds": {
"all": 90
},
"dt": 1485789600,
"sys": {
"type": 1,
"id": 5091,
"message": 0.0103,
"country": "GB",
"sunrise": 1485762037,
"sunset": 1485794875
},
"id": 2643743,
"name": "London",
"cod": 200
}
答案 0 :(得分:0)
JSON属性称为main
而不是mainData
。 JSON.Net找不到名为mainData
的属性,因此不会填充POCO的MainData
属性