Question

我有一个返回数据的ajax函数，我想将objects名称推送到数组中，但是当我检查控制台时，它一直在说未定义。我该如何只打印某些属性？

$.ajax({
      url: 'http://localhost:3000/list',
      type: 'get',
      success: function(response){
        console.log(response);
        console.log(response.name);
      },
      error: function(){
        console.log('err');
      }
    });

当我在控制台上检查结果

//console.log(response);
(3) [{...}, {...}, {...}]
1: {_id: "1", name: "a"}
2: {_id: "2", name: "b"}
3: {_id: "3", name: "c"}

//console.log(response.name);
(3)undefined

Answer 1

您的回复是一个对象，因此您必须标识要显示的内容的索引

  console.log(response[1].name); //will display "b"

Answer 2

您的结果采用array of objects的形式，因此console.log(response.name);对您不起作用。您必须先添加索引，例如response[1]，然后再添加property之类的名称response[1].name，以获得第二个元素的名称，请参见MDN以了解有关属性访问器的更多信息

response[0].name // logs a
response[1].name // logs b
response[2].name // logs c

例如

const response = [{_id: "1", name: "a"},{_id: "2", name: "b"},{_id: "3", name: "c"}]

console.log(response[2].name);

Answer 3

由于每个对象都有3个名称，您是否要全部输出？

const response = [{_id: "1", name: "a"},{_id: "2", name: "b"},{_id: "3", name: "c"}];
console.log(response.map(({name})=>name).join());
// or one at a time
response.forEach(({name}, index)=>console.log(`${index}: "${name}"`));

Ajax调用后未定义

3 个答案: