Question

在输出不在第二个列表中的列表中的项目时遇到以下问题。

代码如下：

def getInitialList(): # Define initial list with the use of requests and BS, will return a set

    getInHtml = requests.get("http://127.0.0.1")
    parseInHtml = BeautifulSoup(getInHtml.content, "html.parser")

    processInHtml = parseInHtml.find_all("div", class_="inner-article")

    firstList = []

    for items in processInHtml:
        firstList.append(items)

    return firstList

def getSecList(): #Define second list with the use of requests and BS, will return a set
    getHtml = requests.get("http://127.0.0.1")
    parseHtml = BeautifulSoup(getHtml.content, "html.parser")

    processHtml = parseHtml.find_all("div", class_="inner-article")

    secList = []

    for items in processHtml:
        secList.append(items)

    return secList

def catch_new_item():

    initList = getInitialList()

    while True:
        if initList == getSecList():
            print("No new items")
        else:
            print("New items found")
            break
    secList = getSecList()
    return set(secList) - set(initList)

最后一个函数（catch_new_items（））应该返回secList中的内容，而不是initList中的内容，但是当我运行它时，它将返回一个空集。

地址127.0.0.1是本地Web服务器，该服务器正在运行以确定这2个项目之间的差异。我要做的就是编辑html并在其中添加一个元素。

让我知道您的想法吗？

Answer 1

我已经以这种方式修改了代码，以对其进行调试：

def getInitialList(): # Define initial list with the use of requests and BS, will return a set

    firstList = ['1', '2', '3']
    return firstList

def getSecList(): #Define second list with the use of requests and BS, will return a set

    secList = ['a', 'b', '3', '1']
    return secList

def catch_new_item():

    initList = getInitialList()
    while True:
        if initList == getSecList():
            print("No new items")
        else:
            print("New items found")
        break
    secList = getSecList()
    return set(secList) - set(initList)

print(catch_new_item())

并返回：

New items found
{'a'}

所以项目检测的逻辑很好。

您只是尝试从getInitialList（）中打印出列表，然后 getSecList（）函数查看它们是否为空？
列表真的包含不同的项目吗？（如果它们不为空，请参阅 p。 1）

2个清单之间的区别

1 个答案: