Question

我有一种方法可以检查用户是否要玩其他游戏，问题是，如果用户输入了无效的输入，则在正确的输入anotherGame之后仍设置为Y

退出该方法时，即使他们输入了错误的输入而选择了anotherGame，Y的值仍然是N

此代码块运行时，anotherGame无论如何都返回Y。

else
{
     Console.WriteLine("ERROR: Invalid input (Y/N) only!");
     promptRedo(anotherGame);
}

代码示例：

using System;

public class Program
{
    public static void Main()
    {
        string anotherGame = "y";
        while (anotherGame == "y")
        {
            anotherGame = promptRedo(anotherGame);
            Console.WriteLine(anotherGame);
        }
    }
    static String promptRedo(String anotherGame)
    {
        Console.Write("Would you like to play another game? (Y/N) => ");
        String input = Console.ReadLine().ToLower();
        if (input.Equals("y"))
        {
            anotherGame = "y";
        }
        else if (input.Equals("n"))
        {
            // get any key from user to exit program
            Console.WriteLine();
            Console.WriteLine("Thank you for playing!");
            Console.WriteLine("Press any key to exit ...");
            Console.ReadKey();
            anotherGame = "n";
            Console.WriteLine(anotherGame);
        }
        else
        {
            Console.WriteLine("ERROR: Invalid input (Y/N) only!");
            promptRedo(anotherGame);
        }
        return anotherGame;
    }
}

Answer 1

您不需要递归调用，只需删除

promptRedo(anotherGame);

从promptRedo函数内部的else节开始。

Answer 2

此函数不需要传递参数。而不是一次又一次地调用函数g只是将其放在循环中：

static String promptRedo()
{ 
    String anotherGame = ""
    do
    {
        Console.Write("Would you like to play another game? (Y/N) => ");
        String input = Console.ReadLine().ToLower();
        if (input.Equals("y"))
        {
            anotherGame = "y";
        }
        else if (input.Equals("n"))
        {
            // get any key from user to exit program
            Console.WriteLine();
            Console.WriteLine("Thank you for playing!");
            Console.WriteLine("Press any key to exit ...");
            Console.ReadKey();
            anotherGame = "n";
            Console.WriteLine(anotherGame);
        }
        else
        {
            Console.WriteLine("ERROR: Invalid input (Y/N) only!");
        }
    } while(anotherGame != "y" && anotherGame != "n")
    return anotherGame;
}

Answer 3

else
{
     Console.WriteLine("ERROR: Invalid input (Y/N) only!");
     promptRedo(anotherGame);
}

在此代码中，您只是调用promptRedo（）并在函数末尾返回anotherGame。但是您应该从hintRedo（）返回。

您的代码必须如下所示

else
{
     Console.WriteLine("ERROR: Invalid input (Y/N) only!");
     return promptRedo(anotherGame);
}

Answer 4

您尚未在else块中将“ promptRedo（anotherGame）”方法分配给“ anotherGame”变量。

代替：

    else
    {
        Console.WriteLine("ERROR: Invalid input (Y/N) only!");
        promptRedo(anotherGame);
    }

您应该写：

     else
    {
        Console.WriteLine("ERROR: Invalid input (Y/N) only!");
        anotherGame = promptRedo(anotherGame);
    }

方法未返回正确值

4 个答案: