Question

我希望根据长度x重复并堆叠到链上的方法；

const thing = ObjWithMethods
thing
  .something()
  .somethingElse()
  .repeat(() => {
    for (let i = 0; i < x; i++) {
      thing.repeatedMethod()
    }
  })
  .endMethods();

有没有办法做到这一点？

编辑：这是我目前的具体示例

import HummusRecipe from 'hummus-recipe';
const getPageCount = require('docx-pdf-pagecount');
const generateFooterText = (index, length) => `Page ${index} / ${length}`;

const applyPdfFooter = (input, output, cb) => {
  const throwErr = (err) => {cb(err);};
  const recipe = new HummusRecipe(input, output, pdfOptions);
  getPageCount(input)
    .then((pages) => {
      console.log('Pages: ', pages);
      recipe
        .and(function(recipe) {
          for (let i = 0; i < pages; i++) {
            const text = generateFooterText(i, pages);
            recipe
              .editPage(i)
              .text(text, 0, 0)
              .endPage();
          }
        })
        .endPDF();
      cb();
    })
    .catch(throwErr);
};
export default applyPdfFooter;

Answer 1

您的配方可以实施为：

 class Recipe {
    constructor(input, output, options) {
      this.page = 0;
    }

    and(fn) {
      fn(this);
      return this; // chaining
   }

   editPage(i) {
     this.page = i;
     return this;
   }

   text(...args) {
    //...
    return this;
   }

   endPage() {
    this.page++;
    return this;
   }

   endPdf() { }
 }

...但是我不确定and(...)方法是否有任何好处...

在方法循环上重复方法链

1 个答案: