Question

我正在使用PHP，HTML和CSS代码进行项目。问题是当我在没有CSS代码的情况下执行它时，它可以工作，但是当我向其中添加CSS时，消息“成功创建”将显示在网页底部的状态栏中！为什么会发生这种情况，为什么不将其显示在页面上？

这是我的HTML代码：

<div class="bg">
    <p><a href = "register.php">Register</a> | <a href="login.php">Login</a></p>
    <h3>Registration Form</h3>
    <form action="register.php" method = "POST">
        Email: <input type = "text" name = "email"><br />
        Username: <input type = "text" name = "user"><br />
        Password: <input type = "password" name = "pass"><br />
        <input type = "submit" value = "Login" name = "submit" />
    </form>
</div>

这是我的PHP代码：

if (isset($_POST["submit"])) {
    $email = $_POST['email'];
    $user = $_POST['user'];
    $pass = $_POST['pass'];

    $connection = mysqli_connect('localhost' , 'root' , '', 'website') or die(mysqli_error());
    mysqli_select_db($connection , "website") or die("can not select database");

    if ($connection) {
        $query = mysqli_query($connection ,"SELECT * FROM users WHERE username = '".$user."'");
        $numOfRows = mysqli_num_rows($query);
        if ($numOfRows == 0){
            $sql = "INSERT INTO users( email ,username , password) VALUES('$email', '$user' , '$pass')";
            $result = mysqli_query($connection , $sql);
            if($result) {
                echo "successfully Created";
            } else {
                echo "failure!";
            }
        } else {
            echo "Username already exist!";
        }
    } else {
        echo "can not connect to database";
    }
}

这是我的CSS代码：

body, html {
    height: 100%;
    margin: 0;
}

.bg {
    background-image: url("SARV.jpg");
    height: 100%; 
    background-position: center;
    background-repeat: no-repeat;
    background-size: cover;
}

Answer 1

因为您以纯文本形式回显而不是将其处理为html代码。看看您的输出html。

如何使PHP和CSS代码协同工作

1 个答案: