你好，我仍然是一个学习者，我面临着编写一个Java代码，该代码用一个包围钻石的框架打印钻石。我已经尝试过制作框架，但是在形成钻石方面遇到了挑战。 Here is a sample of how the diamond should look like
这是我的代码示例：
static int diagonalDifference(int[][] arr) {
int left=0,right=0;
for(int i=0;i<n;i++){
for(int j=0;j<n;j++){
if(i==j){
left=left+arr[i][j];
}
}
}
for(int i=0,int j=n;i<n;i++,j--){
right=right+arr[i][j];
}
}
}
答案 0 :(得分：0)
这里是：
private void drawDimond(int size) {
System.out.print("\n");
// for the top cover
System.out.print("+");
for (int i = 0; i < size * 2 - 1; i++) {
System.out.print("-");
}
System.out.println("+");
//first half
for (int i = 1; i < size; i++) {
System.out.print("|");
for (int j = 0; j < size - i; j++) {
System.out.print("-");
}
for (int k = 0; k < i * 2 - 1; k++) {
System.out.print("*");
}
for (int j = 0; j < size - i; j++) {
System.out.print("-");
}
System.out.println("|");
}
//middle line
System.out.print("|");
for (int i = 0; i < size * 2 - 1; i++) {
System.out.print("*");
}
System.out.println("|");
//second half
for (int i = 1; i < size; i++) {
System.out.print("|");
for (int j = 0; j <= (i * 2 - 1) / 2; j++) {
System.out.print("-");
}
for (int k = 0; k < (size - i) * 2 - 1; k++) {
System.out.print("*");
}
for (int j = 0; j <= (i * 2 - 1) / 2; j++) {
System.out.print("-");
}
System.out.println("|");
}
// For the bottom
System.out.print("+");
for (int i = 0; i < size * 2 - ((size + 1) % 2); i++) {
System.out.print("-");
}
System.out.println("+");
}
有什么问题吗？
答案 1 :(得分：0)
从 -n 到 n 的两个嵌套 for 循环。菱形中心的零点：
public static void main(String[] args) {
for (int i = 0; i <= 7; i++)
printDiamond(i);
}
static void printDiamond(int n) {
System.out.println("n=" + n);
for (int i = -n; i <= n; i++) {
for (int j = -n - 1; j <= n + 1; j++)
// skip middle vertical
if (j == 0) System.out.print("");
// borders:
// vertical borders
else if (Math.abs(j) == n + 1)
if (Math.abs(i) == n) System.out.print("+");
else System.out.print("|");
// horizontal borders
else if (Math.abs(i) == n) System.out.print("-");
// rhombus:
// left middle horizontal ending
else if (i == 0 && j == -n) System.out.print("<");
// right middle horizontal ending
else if (i == 0 && j == n) System.out.print(">");
// upper right and lower left borders
else if (Math.abs(i - j) == n) System.out.print("\\");
// upper left and lower right borders
else if (Math.abs(i + j) == n) System.out.print("/");
// inner rhombus lines
else if (Math.abs(i) + Math.abs(j) < n)
// double central line for odd n
if ((n - i) % 2 != 0) System.out.print("=");
else System.out.print("-");
// whitespace
else System.out.print(" ");
// new line
System.out.println();
}
}
输出（组合）：
n=0 n=1 n=2 n=3 n=4 n=5 n=6 n=7
++ +--+ +----+ +------+ +--------+ +----------+ +------------+ +--------------+
|<>| | /\ | | /\ | | /\ | | /\ | | /\ | | /\ |
+--+ |<-->| | /--\ | | /--\ | | /--\ | | /--\ | | /--\ |
| \/ | |<====>| | /====\ | | /====\ | | /====\ | | /====\ |
+----+ | \--/ | |<------>| | /------\ | | /------\ | | /------\ |
| \/ | | \====/ | |<========>| | /========\ | | /========\ |
+------+ | \--/ | | \------/ | |<---------->| | /----------\ |
| \/ | | \====/ | | \========/ | |<============>|
+--------+ | \--/ | | \------/ | | \----------/ |
| \/ | | \====/ | | \========/ |
+----------+ | \--/ | | \------/ |
| \/ | | \====/ |
+------------+ | \--/ |
| \/ |
+--------------+
答案 2 :(得分：0)
要在一行中获得组合的菱形输出，您可以使用三个嵌套的 for 循环 和几个 if else 语句。
n=1 n=2 n=3 n=4 n=5 n=6 n=7
+--+ +----+ +------+ +--------+ +----------+ +------------+ +--------------+
|<>| | /\ | | /\ | | /\ | | /\ | | /\ | | /\ |
+--+ |<-->| | /--\ | | /--\ | | /--\ | | /--\ | | /--\ |
| \/ | |<====>| | /====\ | | /====\ | | /====\ | | /====\ |
+----+ | \--/ | |<------>| | /------\ | | /------\ | | /------\ |
| \/ | | \====/ | |<========>| | /========\ | | /========\ |
+------+ | \--/ | | \------/ | |<---------->| | /----------\ |
| \/ | | \====/ | | \========/ | |<============>|
+--------+ | \--/ | | \------/ | | \----------/ |
| \/ | | \====/ | | \========/ |
+----------+ | \--/ | | \------/ |
| \/ | | \====/ |
+------------+ | \--/ |
| \/ |
+--------------+
// maximum diamond size
int max = 7;
// title row
for (int n = 1; n <= max; n++) {
System.out.print("n=" + n);
// padding up to the diamond width
for (int a = 0; a < n * 2 - 1; a++)
System.out.print(" ");
// indent after diamond
System.out.print(" ");
}
System.out.println();
// combined rows of diamonds
for (int row = 1; row <= max * 2 + 1; row++) {
// sizes of diamonds
for (int n = 1; n <= max; n++) {
// current diamond row [-n, n]
int i = row - n - 1;
if (i <= n) // elements of the row [-n-1, n+1]
for (int j = -n - 1; j <= n + 1; j++)
if (j == 0) continue; // skip middle vertical
else if (Math.abs(j) == n + 1) // vertical borders & corners
System.out.print(Math.abs(i) == n ? "+" : "|");
else if (Math.abs(i) == n) // horizontal borders
System.out.print("-");
else if (i == 0 && Math.abs(j) == n) // middle left & right tips
System.out.print(j == -n ? "<" : ">");
else if (Math.abs(i - j) == n) // upper right & lower left edges
System.out.print("\\");
else if (Math.abs(i + j) == n) // upper left & lower right edges
System.out.print("/");
else if (Math.abs(i) + Math.abs(j) < n) // inner rhombus lines
System.out.print((n - i) % 2 != 0 ? "=" : "-");
else // whitespace
System.out.print(" ");
else // empty row, current diamond width + borders
for (int a = 0; a < n * 2 + 2; a++)
System.out.print(" ");
// indent after diamond
System.out.print(" ");
}
System.out.println(); // new line
}