Question

我需要从一列中获取最常用的代码（例如）。我尝试此代码，但这不起作用。

$count = Invoice::with('userinvoicesubaccount')->where('person_id',$id)
        ->pluck('codeinvoice');
$count = array_count_values($count);
$count = array_keys($count);
$element = $count[0];

首先，我选择所有值的列表。

Answer 1

// get available 'distinct' codes
$distinct_codes = Invoice::select('codeinvoice')->where('person_id', $id)
            ->groupBy('codeinvoice')
            ->pluck('codeinvoice');

// a collection which will hold count of each code against the code
$code_counts = collect();

// for each code get the number of rows
// and add to the collection
foreach ($distinct_codes as $code) {

     $code_counts->push(collect([
         'code' => $code,
         'count' => Invoice::where(
              ['person_id', $id],
              ['codeinvoice', $code]
         ])->count()
     ]));
}

// get the most used code from that collection
$most_used_code = $code_counts->max->count;

Answer 2

如果codeinvoice是发票表的属性，则可以执行以下操作：

$count = Invoice::selectRaw('invoices.codeinvoice, count(invoices.codeinvoice) as ocurrences')
              ->where('person_id',$id)
              ->groupBy('codeinvoice');

对于每个返回的行，您将拥有代码以及该代码的出现次数。基于此，如果您只想要最常用的，则可以像这样使用order by和limit：

$count = Invoice::selectRaw(invoices.codeinvoice, count(invoices.codeinvoice) as ocurrences')
              ->where('person_id',$id)
              ->orderBy('ocurrences', 'desc')
              ->groupBy('codeinvoice')
              ->limit(1);

然后，返回的唯一一行将是最常用的代码。

我希望那是你想要的。

Laravel从列中获取频率

2 个答案: