在自己的类中访问对类的引用

Question

在下面的代码中，如何在未在其自己的类内显式指定关键字“用户”的情况下访问变量User ？

class User {
  say = () => {
    // Here, I have to explicitly write "User". Is there
    // some javascript trick to get the class reference inside 
    // its own class without explicitly writing the name?
    console.log(User);
  }
}