Question

在MySQL中，我有一个看起来像这样的表：这有点复杂，因为mysql不支持排名窗口功能，甚至不支持CTE，因此我尝试使用while循环实现

如果导入的和节之间存在任何关系，则应将它们分组在一起。根据关系，它们应分为1,2,3,4，....

但是在这种情况下，我的rn始终为1，并且不确定为什么它不递增。您能帮我查看此查询吗？我不确定该如何解决。

示例创建脚本：

    create table temp1 (
    id int, imported int, section int, rn int, checked int default 0
    );
    insert into temp1(id, section, rn)           values (204, 718, 0);
    insert into temp1(id, imported, section, rn) values (997,718,034,0);
    insert into temp1(id, imported, section, rn) values (998,034,055,0);
    insert into temp1(id, imported, section, rn) values (111,453,234,0);
    insert into temp1(id, section, rn) values (908, 453,0);
    insert into temp1(id, imported, section, rn) values (231,234,890,0);
    insert into temp1(id, section, rn) values (342, 567,0);

我的最终结果应类似于：

我已经尝试过使用while循环来创建存储过程：

    DROP PROCEDURE IF EXISTS sp_recursiveimport;
    Delimiter $$
    CREATE PROCEDURE sp_recursiveimport()  -- (IN rnX integer)
    BEGIN
    DECLARE n INT DEFAULT 0;   DECLARE i,j,k INT DEFAULT 0;    SELECT COUNT(*) FROM temp1 INTO n;
    SET i=0; set @rn = 1; --  set @k = 0;
    WHILE i<n DO 
    set j = 0; select i;
      set @sec = (select ifnull(section,0) FROM temp1 LIMIT i,1);          
      set @imp = (select ifnull(imported,0) FROM temp1 LIMIT i,1); select @imp, @sec;
        update1: while j<n do   select j;
    --         if j=0 then
               if (select ifnull(imported,0) from temp1 limit j,1) = @sec and (select checked from temp1 limit j,1) = 0 then 
               set @update  = concat('update temp1 set rn = 1, checked = 1 where imported = ',@sec); select @update;    PREPARE stmt_name FROM @update;     EXECUTE Stmt_name;     DEALLOCATE prepare stmt_name;
               set @update1 = concat('update temp1 set rn = 1, checked = 1 where section = ',@sec); select @update1;   PREPARE stmt_name FROM @update1;     EXECUTE Stmt_name;     DEALLOCATE prepare stmt_name;
               set k = j;
               end if;
               if (select ifnull(section,0)          from temp1 limit j,1) = @imp and (select checked from temp1 limit j,1) = 0 then 
               set @update3 = concat('update temp1 set rn = 1, checked = 1 where section = ',@imp);  select @update3;    PREPARE stmt_name FROM @update3;     EXECUTE Stmt_name;     DEALLOCATE prepare stmt_name;
               set @update4 = concat('update temp1 set rn = 1, checked = 1 where imported = ',@imp); select @update4;    PREPARE stmt_name FROM @update4;     EXECUTE Stmt_name;     DEALLOCATE prepare stmt_name;
               set k = j;
               end if;

    --            set @sec = (select ifnull(imported,0) from temp1 limit k,1);
    --            set @imp = (select ifnull(section,0)          from temp1 limit k,1); select @sec, @imp;
        set j= j+1;
        end while update1;

      set i = i + 1;
    END WHILE;
    END;
    $$
    delimiter;

不确定为什么它不起作用。

使用while循环在条件上分组多行

0 个答案: