Question

我有一个for循环，如下所示：

public static Configuration CreateFromDictionary(Dictionary<string, string> dict)
{
    var mappings = new Dictionary<string, Action<Configuration, string>>
    {
        [nameof(Name)] = (x, value) => x.Name = value,
        [nameof(Url)] = (x, value) => x.Url = value,
        [nameof(Password)] = (x, value) => x.Password = value,
    };

    var missingKeys = mappings.Keys
        .Except(dict.Keys)
        .ToArray();
    if (missingKeys.Any())
        throw new KeyNotFoundException("The given keys are missing: " + string.Join(", ", missingKeys));

    return mappings.Aggregate(new Configuration(), (config, mapping) =>
    {
        mapping.Value(config, dict[mapping.Key]);
        return config;
    });
}

这个数字每天都在增加。我希望这一步是一个星期。可以跳过6天，但这真是太糟糕了。该怎么做？

for mydate in daterange (startDate, endDate):

Answer 1

只需将步长添加到您的循环中即可：

from datetime import timedelta, date

def daterange(start_date, end_date):
     for n in range(0, int((end_date - start_date).days) + 1, 7):
         yield start_date + timedelta(n)

start_dt = date(2018, 9, 1)
end_dt = date(2018, 10, 30)
for dt in daterange(start_dt, end_dt):
    print(dt.strftime("%Y-%m-%d"))

输出：

Answer 2

您使用范围为7的范围对象，并将其添加到开始日期：

import datetime

def daterange(startdate, enddate, steps=1): 
    """Yields dates in increments of steps days from startdate to enddate"""
    numdays = (enddate-startdate).days 
    for x in range (0, numdays, steps):
        yield startdate + datetime.timedelta(days = x)


today = datetime.datetime.today() 
end = today + datetime.timedelta(days=40)

print( list(daterange(today, end, 7)))

输出：

[datetime.datetime(2018, 9, 28, 19, 34, 26, 976681), 
 datetime.datetime(2018, 10, 5, 19, 34, 26, 976681), 
 datetime.datetime(2018, 10, 12, 19, 34, 26, 976681), 
 datetime.datetime(2018, 10, 19, 19, 34, 26, 976681), 
 datetime.datetime(2018, 10, 26, 19, 34, 26, 976681), 
 datetime.datetime(2018, 11, 2, 19, 34, 26, 976681)]

如何在for循环（日期时间）中步进一周（7天）

2 个答案: