尝试创建表1数据存储方式不同的方法

Question

aaiaflat_final

ID   Data  
1    [2,96,801]  

Engine_willie2

ID   Data  Eng  
1    2     3.0  
1    96    4.0  
1    801   4.6  
1    999   5.0  

---

Select  
Engine_willie2.ID,  
(  
CASE   
WHEN Engine_willie2.Data = aaiaflat_final.Data   
THEN Engine_willie.Data END  
)   
AS Data,  
(  
CASE   
WHEN Engine_willie2.Data = aaiaflat_final.Data   
THEN Engine_willie.Eng END  
)   
AS Eng  

FROM aaiaflat_final  

Left Join Engine_willie2 ON   
Engine_willie2.ID = aaiaflat_final.ID  

WHERE  

aaiaflat_final.ID <> ''  

---

我希望查询看起来像这样

ACES_Query

ID   Data  Eng   
1    2     3.0  
1    96    4.0  
1    801   4.6  

我不确定如何解析aaiaflat_final表中的[2,96,801]，因为如果Data为2或与Engine_willie2中的data列有任何其他完全匹配的数据，查询将正常运行。

任何帮助将不胜感激。

Answer 1

加入id上的表，使用replace()除去括号，然后find_in_set()从样本数据中产生所需的结果。

SELECT e.id,
       e.data,
       e.eng
       FROM engine_willie2 e
            INNER JOIN aaiaflat_final a
                       ON a.id = e.id
       WHERE find_in_set(e.data, replace(replace(a.data, '[', ''), ']', ''));