如何使用Php

Question

我在php文件中嵌入了一个json文件，我想从json文件中的表单添加新信息...

我的表单是

<form action="process.php" method="POST">
	First name:<br>
	<input type="text" name="firstName">
	<br><br/>
	Last name:<br>
	<input type="text" name="lastName">
	<br><br>
	  
	Email:<br>
	<input type="text" name="email">
	<br><br>
	  
	Mobile:<br>
	<input type="text" name="mobile">
	<br><br>
	  
	  
	<input type="submit" value="Submit">
</form>

并且php文件是

<?php
   
   $myFile = "data.php";
   $arr_data = array(); // create empty array

  try
  {
	   //Get form data
	   $formdata = array(
	      'firstName'=> $_POST['firstName'],
	      'lastName'=> $_POST['lastName'],
	      'email'=>$_POST['email'],
	      'mobile'=> $_POST['mobile']
	   );

	   //Get data from existing json file
	   $jsondata = file_get_contents($myFile);

	   // converts json data into array
	   $arr_data = json_decode($jsondata, true);

	   // Push user data to array
	   array_push($arr_data,$formdata);

       //Convert updated array to JSON
	   $jsondata = json_encode($arr_data, JSON_PRETTY_PRINT);
	   
	   //write json data into data.json file
	   if(file_put_contents($myFile, $jsondata)) {
	        echo 'Data successfully saved';
	    }
	   else 
	        echo "error";

   }
   catch (Exception $e) {
            echo 'Caught exception: ',  $e->getMessage(), "\n";
   }

?>

当我单击“提交”按钮时，将按如下所示添加新数据

{
    "heroes": [
        {
            "firstName": "Vijay",
            "lastName": "reddy",
            "email": "asdv@ymail.com",
            "mobile": ""
        },
        {
            "firstName": "Paki",
            "lastName": "Webb",
            "email": "vahodid@yahoo.com",
            "mobile": "66464646464"
        },
        {
            "firstName": "sagar",
            "lastName": "rawal",
            "email": "searchbbc1881@gmail.com",
            "mobile": "98989898"
        }
    ],
    "0": {
        "firstName": "sagar",
        "lastName": "rawal",
        "email": "searchbbc1881@gmail.com",
        "mobile": "98989898"
    },
    "1": {
        "firstName": "Purnima",
        "lastName": "rawal",
        "email": "searchbbc1881@gmail.com",
        "mobile": "98652845"
    }
}

但是我想将数据作为

{
    "heroes": [
        {
            "firstName": "Vijay",
            "lastName": "reddy",
            "email": "asdv@ymail.com",
            "mobile": ""
        },
        {
            "firstName": "Paki",
            "lastName": "Webb",
            "email": "vahodid@yahoo.com",
            "mobile": "66464646464"
        },
        {
            "firstName": "sagar",
            "lastName": "rawal",
            "email": "searchbbc1881@gmail.com",
            "mobile": "98989898"
        },
        {
           "firstName": "sagar",
           "lastName": "rawal",
           "email": "searchbbc1881@gmail.com",
           "mobile": "98989898"
        },
        {
           "firstName": "Purnima",
           "lastName": "rawal",
           "email": "searchbbc1881@gmail.com",
           "mobile": "98652845"
       }
   ]
}

即删除索引并将新数据与其他数据一起写入json内...到目前为止我做不到...所以请帮助我...

Answer 1

您只是对整个json数组执行了array_push，您希望将其放入“英雄”中

// converts json data into array
$arr_data = json_decode($jsondata, true);
$arr_data['heroes'][] = $formdata; // Will push $formdata inside 'heroes' array from json 

如果您更喜欢使用array_push，请执行以下操作：

// converts json data into array
$arr_data = json_decode($jsondata, true);
array_push($arr_data['heroes'], $formdata); // Will push $formdata inside 'heroes' array from json 

Answer 2

更改此

 array_push($arr_data,$formdata)

对此

 array_push($arr_data['heroes'],$formdata)