Question

我选择了微服务。我有通用的API可以与任何微服务通信，并使用jerkson JSON库。

import com.codahale.jerkson.Json

case class ApiResult[T](
                         private val content: Option[String],
                         private val error: Option[Throwable]
                       ) {
  def getRaw: String = this.content.getOrElse("null")

  def get()(implicit m: Manifest[T]): T = {
       Json.parse[T](this.content.get)
  }
  def either(implicit m: Manifest[T]): Either[Throwable, T] = error match {
    case None    => Right(get)
    case Some(e) => Left(e)
  }

}

现在我有一个单例，该单例中包含用于命中另一项服务的路由的方法列表。

object PurchasesTrait extends ApiResource {

def getData(payload: String): ApiResult[ProductPurchaseResponse] = 
r[ProductPurchaseResponse](POST, Url.core + "reports/productspurchased", payload)

 }
}

我有两个案例类，

案例类QualifyingProductSummary（upcCode：字符串，描述：Option [String]，购买：Option [Double]）案例类ProductPurchaseResponse（qualifyingProducts：List [QualifyingProducts]，计数：Int）

purchaseTrait.getData(payload) will give me the ApiResult(json, Nnone)

json：

{"qualifyingProductSummary":[{"upcCode":"6410077902","description":"Mini-Wheats Original","purchase":15.2},{"upcCode":"6410044886","description":"Corn Pops","purchase":13.7},{"upcCode":"041570055830","description":"Unsweetened Vanilla Beverage ","purchase":13.5},{"upcCode":"626027087802","description":"Organic Almond Milk Original","purchase":12.5}],"totalQualifyingProducts":19}

val data = purchaseTrait.getData(payload).either

要在我使用ApiResult时从ApiResult中获取数据，

由于合格产品，它无法在 ProductPurchaseResponse 中进行解析。那么如何使用相同的库来实现呢？我希望通用方法也可以对其他嵌套JSON执行相同的操作。

谢谢。

如何创建解析嵌套json的通用方法？

0 个答案: