Question

我真的不知道该怎么说，除了：这项工作有效吗，我可以像布什声明那样在其中添加更多内容吗？

class Enemy():

def __init__(self, name, HP, skills, attack, defense, loot, expget, flvrtxt):
    self.name = name
    self.HP = health
    self.skills = skills
    self.attack = attack
    self.defense = defense
    self.loot = loot
    self.expget = expget
    self.flvrtxt = text

bush = Enemy()
bush.name = "Bush"
bush.HP = 10
bush.skills = "none"
bush.attack = 0
bush.defense = 5
bush.loot = "A stick"
bush.expget = 50
bush.flvrtxt = "Just a bush, it cannot attack"

通过添加更多内容，我的意思是我基本上可以复制并粘贴灌木丛定义，更改统计信息并结成新敌人吗？例如，我可以添加这个吗？：

imp = Enemy():
imp.name = "Imp"
imp.HP = 50
imp.skills = "none"
imp.attack = 10
imp.defense = 10
imp.loot = "gold"
imp.expget = 150
imp.flvrtxt = "Cliche RPG enemy"

Answer 1

在我的脑海中，我可以想到两种方法，具体取决于您要实现的目标。

现在，通过代码的结构化方式，可以创建Enemy类的实例，该实例由其参数定义。正如@Patrick Haugh在评论部分中指出的那样，如果将方法更新为标题为Enemy的方法，则可以在构造时显式设置__init__(self, name, HP, skills, attack, defense, loot, expget, flvrtxt)的所有属性：

class Enemy(object):

    def __init__(self, name, HP, skills, attack, defense, loot, expget, flvrtxt):
        self.name = name
        self.HP = HP
        self.skills = skills
        self.attack = attack
        self.defense = defense
        self.loot = loot
        self.expget = expget
        self.flvrtxt = flvrtext


bush = Enemy("Bush", 10, "none", 0, 5, "A Stick", 50, "Just a bush, it cannot attack")
imp = Enemy("Imp", 50, "none", 10, 10, "gold", 150, "Cliche RPG enemy")

或者，如果您要实例化Bush和Imp的特定类型，则可能希望将它们创建为自己的类，以它们作为Enemy类的子类。自己的关联字段的默认实现：

class Bush(Enemy):

    def __init__(self):
        super(Bush, self).__init__("Bush", 10, "none", 0, 5, "A Stick", 50, "Just a bush, it cannot attack")

class Imp(Enemy):

    def __init__(self):
        super(Imp, self).__init__("Imp", 50, "none", 10, 10, "gold", 150, "Cliche RPG enemy")

通过这种方式，您可以编写类似以下的代码，以实例化一个Bush，该{-{1}}会预先填充您在其类中为Bush定义的所有字段：

bush = Bush();

试图让班级定义敌人

1 个答案: