Question

我遇到以下问题：我得到了JSON输入

{
 "Vorname":"Vorname1 Vorname2",
 "Name":"Nachname
}

输出应为：

{ "such":"NachnameVorname1Vorname2" }

我的JOLT规范是：

 [{
    "operation": "modify-default-beta",
    "spec": {
        "FullName": "=concat(@(1,Vorname),' ' ,@(1,Name))",
        "RFullName": "=concat(@(1,Name),@(1,Vorname))"
    }
}, {
    "operation": "shift",
    "spec": {
        "PersNr": "ymitarb",
        "Austrittsdatum": "ymaust",
        "RFullName": "such",
        "FullName": "name"

    }
}, {
    "operation": "default",
    "spec": {
        "name": "${fname}",
        "such":"$(rfname)",
        "ymitarb": "${nummer}"
    }
}]

我得到的输出是：

{
    "such": "NachnameVorname1 Vorname2",
    "name": "Vorname1 Vorname2 Nachname",
    "ymitarb": ""
}

它应该是{“ such”：“ NachnameVorname1Vorname2”}

我的第二个想法是将Vorname拆分为Vorname_x

[{
    "operation": "modify-default-beta",
    "spec": {
        "FullName": "=concat(@(1,Vorname),' ' ,@(1,Name))",
        "RFullName": "=concat(@(1,Name),@(1,Vorname))"
    }
}, {
    "operation": "shift",
    "spec": {
         "Vorname": {
        "* * *": {
          "$(0,1)": "Vorname_1",
          "$(0,2)": "Vorname_2",
          "$(0,3)": "Vorname_3"
        },
           "* *": {"$(0,1)": "Vorname_1",
          "$(0,2)": "Vorname_2"}


      },
        "PersNr": "ymitarb",
        "Austrittsdatum": "ymaust",
        "RFullName": "such",
        "FullName": "name"

    }
}, {
    "operation": "default",
    "spec": {
        "name": "${fname}",
        "such":"$(rfname)",
        "ymitarb": "${nummer}"
    }
}]

这里的输出是

{
    "Vorname_1": "Vorname1",
    "Vorname_2": "Vorname2",
    "such": "NachnameVorname1 Vorname2",
    "name": "Vorname1 Vorname2 Nachname",
    "ymitarb": ""
}

我无法在concat中使用Vorname_1和Vorname_2的值。由于我无法找到任何解决方案

有任何帮助：）！

Answer 1

规格

[
  {
    "operation": "shift",
    "spec": {
      // split Vorname by a space
      "Vorname": {
        "* *": {
          "$(0,1)": "vorFront",
          "$(0,2)": "vorBack"
        }
      },
      // pass Name thru
      "Name": "Name"
    }
  },
  {
    "operation": "modify-default-beta",
    "spec": {
      // concat the names now that the space is gone
      "such": "=concat(@(1,Name),@(1,vorFront),@(1,vorBack))"
    }
  }
]

Answer 2

那是我的规格：

 [{
        "operation": "modify-default-beta",
        "spec": {
            "FullName": "=concat(@(1,Vorname_1),' ',@(1,Vorname_2),' ',@(1,Vorname_3),' ',@(1,Name))",
            "RFullName": "=concat(@(1,Name),@(1,Vorname_1),@(1,Vorname_2),@(1,Vorname_3))"
        }
    }, {
        "operation": "shift",
        "spec": {
            "Vorname": {
                "* * *": {
                    "$(0,1)": "Vorname_1",
                    "$(0,2)": "Vorname_2",
                    "$(0,3)": "Vorname_3"
                },
                "* *": {
                    "$(0,1)": "Vorname_1",
                    "$(0,2)": "Vorname_2"
                }


            },
            "Vorname": "Vorname",
            "PersNr": "ymitarb",
            "Name": "Name",
            "Austrittsdatum": "ymaust",
            "RFullName": "such",
            "FullName": "name"

        }
    }, {
        "operation": "default",
        "spec": {
            "name": "${fname}",
            "such": "${rfname}",
            "ymitarb": "${nummer}"
        }
    }]

输入是：

{
    "Vorname": "Hans Jürgen",
    "Name": "Franz"
}

我得到的输出是：

{
    "Vorname": "Hans Jürgen",
    "Name": "Franz",
    "such": "Franz",
    "name": "  Franz",
    "ymitarb": ""
}

输出应为：

{
    "Vorname_1": "Hans"           //somehow vorname_1 and vorname_2 dosnt work if i  
    "Vorname_2": " Jürgen"       // change your spec
    "Vorname": "Hans Jürgen",
    "Name": "Franz",
    "such": "FranzJürgenHans",
    "name": "Hans Jürgen Franz",
    "ymitarb": ""
}

我在做什么错？另外，如果“ vorname”有1个空格或2个空格，则它的工作方式但是如果规范还不接受空格，应该怎么看？

"*": {
"$(0,1)": "Vorname_1"
}

辛苦工作

使用JOLT传输Json输出时出现问题

2 个答案: