Question

我有一个子图子图。外部子图由一行乘两列组成，两个内部子图分别由四行和四列组成。假设我想要仅与第一个2x2内部子图相对应的图例标签。我该怎么做呢？我的尝试如下：

import numpy as np
import matplotlib.pyplot as plt
import matplotlib.gridspec as gridspec

outerD = dict(nrows=1, ncols=2)
innerD = dict(nrows=2, ncols=2)
D = dict(inner=innerD, outer=outerD)

def initialize_dubsub(D, figsize=None):
    """ """
    fig = plt.figure(figsize=figsize)
    outerG = gridspec.GridSpec(D['outer']['nrows'], D['outer']['ncols'], wspace=0.2, hspace=0.2, width_ratios=[5, 5])
    axes = []
    for n in range(D['inner']['nrows']):
        inner = gridspec.GridSpecFromSubplotSpec(D['inner']['nrows'], D['inner']['ncols'], subplot_spec=outerG[n], wspace=0.25, hspace=0.3, width_ratios=[10, 10], height_ratios=[2, 2])
        for m in range(D['inner']['nrows']*D['inner']['ncols']):
            ax = plt.Subplot(fig, inner[m])
            ax.plot([], [], label='{}x{}'.format(n, m))
            ax.set_xticks([])
            ax.set_yticks([])
            axes.append(ax)
            fig.add_subplot(ax)
    # handles, labels = axes[:4].get_legend_handles_labels() # first 2x2
    # fig.legend(handles=handles, labels=labels, loc='lower center')
    fig.legend(loc='lower center', ncol=4, mode='expand')
    plt.show()
    plt.close(fig)

initialize_dubsub(D)

此代码将输出8 handles和8 labels，而我要每个4。我注释了get_legend_handles_labels()方法，因为它不适用于数组。

我知道我可以做ax.legend()，但是我更喜欢使用fig.legend(...)。我该如何实现？

Answer 1

您可以仅循环遍历该数组中的轴，然后将这四个子图中的句柄和标签附加到列表中，而不必尝试在所需的子图中的数组上调用.get_legend_handles_labels。

例如：

import numpy as np
import matplotlib.pyplot as plt
import matplotlib.gridspec as gridspec

outerD = dict(nrows=1, ncols=2)
innerD = dict(nrows=2, ncols=2)
D = dict(inner=innerD, outer=outerD)

def initialize_dubsub(D, figsize=None):
    """ """
    fig = plt.figure(figsize=figsize)
    outerG = gridspec.GridSpec(D['outer']['nrows'], D['outer']['ncols'], wspace=0.2, hspace=0.2, width_ratios=[5, 5])
    axes = []
    for n in range(D['inner']['nrows']):
        inner = gridspec.GridSpecFromSubplotSpec(D['inner']['nrows'], D['inner']['ncols'], subplot_spec=outerG[n], wspace=0.25, hspace=0.3, width_ratios=[10, 10], height_ratios=[2, 2])
        for m in range(D['inner']['nrows']*D['inner']['ncols']):
            ax = plt.Subplot(fig, inner[m])
            ax.plot([], [], label='{}x{}'.format(n, m))
            ax.set_xticks([])
            ax.set_yticks([])
            axes.append(ax)
            fig.add_subplot(ax)
    handles, labels = [], []
    for ax in axes[:4]:
        handles_, labels_ = ax.get_legend_handles_labels()
        handles += handles_
        labels += labels_
    fig.legend(handles=handles, labels=labels, loc='lower center')
    #fig.legend(loc='lower center', ncol=4, mode='expand')
    plt.show()
    plt.close(fig)

initialize_dubsub(D)

Answer 2

尝试更换

ax.plot([], [], label='{}x{}'.format(n, m))

作者

ax.plot([], [], label=('' if n==0 else '_') + '{}x{}'.format(n, m))

如果我了解您的设置正确...

如何从子图内的指定子图中选择图例手柄和标签？

2 个答案: