Question

在我使用pyasn创建的Python类之后，我希望看到将值通过文件而不是通过创建对象并将成员的值通过object传递的方式的可行性。value的类型是字符串和数字将出现在excel工作表中，这意味着所有值不是另一个模式的参数都将出现在excel工作表中（模式表示类似Credit_card的类）

from pyasn1.type import univ, char, namedtype, namedval, tag, constraint, useful


class Card_type(univ.Enumerated):
    pass


Card_type.namedValues = namedval.NamedValues(
    ('cb', 0),
    ('visa', 1),
    ('eurocard', 2),
    ('diners', 3),
    ('american-express', 4)
)


class Client(univ.Sequence):
    pass


Client.componentType = namedtype.NamedTypes(
    namedtype.NamedType('name', char.PrintableString().subtype(subtypeSpec=constraint.ValueSizeConstraint(1, 20)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 0))),
    namedtype.OptionalNamedType('street', char.PrintableString().subtype(subtypeSpec=constraint.ValueSizeConstraint(1, 50)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 1))),
    namedtype.NamedType('postcode', char.NumericString().subtype(subtypeSpec=constraint.ValueSizeConstraint(5, 5)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 2))),
    namedtype.NamedType('town', char.PrintableString().subtype(subtypeSpec=constraint.ValueSizeConstraint(1, 30)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 3))),
    namedtype.DefaultedNamedType('country', char.PrintableString().subtype(subtypeSpec=constraint.ValueSizeConstraint(1, 20)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 4)).subtype(value="France"))
)


class Credit_card(univ.Sequence):
    pass


Credit_card.componentType = namedtype.NamedTypes(
    namedtype.NamedType('type', Card_type().subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 0))),
    namedtype.NamedType('number', char.NumericString().subtype(subtypeSpec=constraint.ValueSizeConstraint(20, 20)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 1))),
    namedtype.NamedType('expiry-date', char.NumericString().subtype(subtypeSpec=constraint.ValueSizeConstraint(6, 6)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 2)))
)


class Payment_method(univ.Choice):
    pass


Payment_method.componentType = namedtype.NamedTypes(
    namedtype.NamedType('check', char.NumericString().subtype(subtypeSpec=constraint.ValueSizeConstraint(15, 15)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 0))),
    namedtype.NamedType('credit-card', Credit_card().subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatConstructed, 1))),
    namedtype.NamedType('cash', univ.Null().subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 2)))
)


class Order_header(univ.Sequence):
    pass


Order_header.componentType = namedtype.NamedTypes(
    namedtype.NamedType('reference', char.NumericString().subtype(subtypeSpec=constraint.ValueSizeConstraint(12, 12)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 0))),
    namedtype.NamedType('date', char.NumericString().subtype(subtypeSpec=constraint.ValueSizeConstraint(8, 8)).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 1))),
    namedtype.NamedType('client', Client().subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatConstructed, 2))),
    namedtype.NamedType('payment', Payment_method().subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatConstructed, 3)))
)


class Order(univ.Sequence):
    pass


Order.componentType = namedtype.NamedTypes(
    namedtype.NamedType('header', Order_header().subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatConstructed, 0))),
    #namedtype.NamedType('items', univ.SequenceOf(componentType=Order_line()).subtype(implicitTag=tag.Tag(tag.tagClassContext, tag.tagFormatSimple, 1)))
)




a=Order()
a['header']['reference']='abcdefghixcv'
print a

#Output
Order:
 header=Order_header:
  reference=abcdefghixcv

我们可以通过诸如excel之类的文件将上述示例的asn值传递给吗？就像引用'abcdefghixcv'一样。

Answer 1

问题：能否通过文件传递上述示例的asn值

给出以下从任何文件中检索到的数据：

注意：在此示例中，client_data被保存在用id == 12345引用的第二个文件中！ data值已分配给NamedType和class Order['header']的{{1}}。

class Client

为简便起见，我将您的类定义简化为仅使用的部分。

client_data = {'12345':{'name':'John', 'town':'New York'}}
data = {'reference': 'abc', 'date': '2018-10-03', 'client': '12345', 'payment': 'cash'}

我假设可以从class NumericString(): def __init__(self, value): self.value = value def __str__(self): return self.value def __new__(arg): obj = object.__new__(NumericString) obj.__init__(arg) return obj class Payment_method(): def __init__(self, method): self.method = method def __str__(self): return self.method def __new__(arg): obj = object.__new__(Payment_method) obj.__init__(arg) return obj class Client(): def __init__(self, data): self.data = data def __str__(self): return ", ".join(self.data.values()) def __new__(id): obj = object.__new__(Client) obj.__init__(id) return obj中检索以下asn1_schema，但是为简单起见，我手动定义了它。

class Order()

此示例绑定到数据，这意味着Dict asn1_schema = {'reference':NumericString, 'date':NumericString, 'client':Client, 'payment':Payment_method}知道必须创建哪个data类。因此，不需要预定义的Order['header']。

Order

输出：

# For simplicity, define order as a 'dict'
order = {'header':{}}

# Loop over the given data dict
for key in data:
    # Create a class maped from asn1_schema and pass data value
    if key == 'client':
        # For client pass data from 'client_data' using 'id'
        cls = asn1_schema[key].__new__(client_data[data[key]])
    else:
        cls = asn1_schema[key].__new__(data[key])

    # Update order header with this 'NamedType'
    order['header'][key] = cls

# Show the resulting order header
for key in order['header']:
    types = order['header'][key]
    print("{:10}:\t{:14}:\tvalue:{}".format(key, types.__class__.__name__, types))

经过Python：3.5.3

的测试

通过诸如excel之类的文件填充值

1 个答案: