Question

我查询了最早7天的获取数据，但失败了，提示“之间”。我的查询：

SELECT b.sequence_number, b.message
FROM test.tab1 a, test.tab2 b
WHERE a.id = b.id 
AND a.delivery_date between (select min(delivery_date) from test.tab1) 
and (select min(delivery_date)-7 from test.tab1)

，但此查询无法获得结果。如何解决此问题？

Answer 1

您需要确定订单之间的顺序，较小的应该是第一个，然后是较大的

SELECT b.sequence_number, b.message
FROM test.tab1 a, test.tab2 b
WHERE a.id = b.id 
AND a.delivery_date between (select min(delivery_date)-7 from test.tab1)
and (select min(delivery_date) from test.tab1)

Answer 2

如果您希望从当前日期开始最近7天的记录，则查询为

    SELECT b.sequence_number, b.message
    FROM test.tab1 a, test.tab2 b
    WHERE a.id = b.id 
    AND a.delivery_date>=current_date - interval '7 days'

但是如果要从您的最短日期开始7天，那应该是

SELECT b.sequence_number, b.message
        FROM test.tab1 a, test.tab2 b
        WHERE a.id = b.id 
        AND a.delivery_date>=(select min(delivery_date)-7 from test.tab1) and a.delivery_date <=(select min(delivery_date) from test.tab1)

取得7天最久的记录

2 个答案: