Question

从json到java对象的转换失败。更新到杰克逊版本2.9.7后失败。

 @JsonTypeInfo(use = JsonTypeInfo.Id.CLASS, include = 
     JsonTypeInfo.As.PROPERTY, property = "className")
 public class DefaultValidator implements Validator {}


  ObjectMapper objectMapper=new ObjectMapper(); 
  objectMapper.configure(SerializationFeature.FAIL_ON_EMPTY_BEANS, false);
  objectMapper.configure(SerializationFeature.FAIL_ON_UNWRAPPED_TYPE_IDENTIFIERS, false);
  objectMapper.setVisibilityChecker(VisibilityChecker.Std.defaultInstance()
            .withFieldVisibility(JsonAutoDetect.Visibility.ANY)
            .withGetterVisibility(JsonAutoDetect.Visibility.NONE)
            .withCreatorVisibility(JsonAutoDetect.Visibility.NONE));
  obj = objectMapper.readValue(jsonBody, clazz);`

UIRowInput {private DefaultValidator rowCommmonValidator;}

以下是例外情况：

未识别的字段“ @class”（类com.fe.core.validator.DefaultValidator），未在[来源：（StringReader）处标记为可忽略（0个已知属性：]）；行：1，列：3043]（通过参考链：com.ui.request.input.UpdateGraphInputRequest [“ graphInput”]-> com.model.ui.graph.UIGraphInput [“ nodeInputs”]-> java.util.ArrayList [0]-> com.model.ui.graph.item.node.UINodeInput [“ nodeInputs]]-> java.util.ArrayList [0]-> com.model.ui.graph.item.node.UINodeInput [” lineItemInputs“]-> java.util.ArrayList [0]-> com.model.ui.graph.item.lineItem.UILineItemInput [” tabInput“]-> com.model.ui.graph.item.lineItem.matrix.UITabInput [“ rowInputs”]-> java.util.ArrayList [0]-> com.model.ui.graph.item.lineItem.matrix.UIRowInput [“ rowCommmonValidator”]-> com.fe.core.validator.DefaultValidator [“ @class“]）

谢谢！

无法识别的字段“ className”，@ JsonTypeInfo

0 个答案: