在Python中如何将字符串转换为带有时区的日期时间

时间:2018-09-28 04:38:36

标签: python python-2.7 python-datetime

将字符串转换为日期时间时,出现值错误。任何人都可以帮助解决此问题。

>>> from datetime import datetime
>>> date_str = "2018-07-13T17:12:02-0500"
>>> t = datetime.strptime(date_str, "%Y-%m-%dT%H:%M:%S%z")

Traceback (most recent call last):
File "<pyshell#27>", line 1, in <module>
t = datetime.strptime(date_str, "%Y-%m-%dT%H:%M:%S%z")
File "C:\Python27\lib\_strptime.py", line 324, in _strptime
(bad_directive, format))
ValueError: 'z' is a bad directive in format '%Y-%m-%dT%H:%M:%S%z'

>>> t = datetime.strptime(date_str, "%Y-%m-%dT%H:%M:%S%Z")

Traceback (most recent call last):
File "<pyshell#28>", line 1, in <module>
t = datetime.strptime(date_str, "%Y-%m-%dT%H:%M:%S%Z")
File "C:\Python27\lib\_strptime.py", line 332, in _strptime
(data_string, format))
ValueError: time data '2018-07-13T17:12:02-0500' does not match format '%Y- 
%m-%dT%H:%M:%S%Z'
>>>

我正在使用python版本2.7.14

1 个答案:

答案 0 :(得分:0)

from datetime import datetime
iso_ts = '2012-11-01T04:16:13-04:00'
datetime.strptime(''.join(iso_ts.rsplit(':', 1)), '%Y-%m-%dT%H:%M:%S%z')
datetime.datetime(2012, 11, 1, 4, 16, 13, 
tzinfo=datetime.timezone(datetime.timedelta(-1, 72000)))
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