Question

我具有以下实体结构

public class Application {
    @JoinColumn(name = "account_id")
    @ManyToOne
    private Account account;

    @JoinColumn(name = "involved_account_id")
    @ManyToOne
    private Account involvedAccount;
}

public class Account {
    private string id;
    private string name;
}

我想获取account名称或involvedAccount名称与给定帐户名匹配的所有应用程序。

CriteriaQuery<Application> query = cb.createQuery(Application.class);
Root<Application> root = query.from(Application.class);

Predicate conditions = cb.conjunction();

conditions = cb.and(conditions, cb.or(
    cb.like(
        cb.upper(root.get("account").get("name")), 
        accountName.toUpperCase()
    ), cb.like(
        cb.upper(root.get("involvedAccount").get("name")), 
        accountName.toUpperCase())
    )
);

query.where(conditions);
query.select(root);

但是上面的代码在以下情况下产生了以下情况：将and用作主键而不是or

where applicati0_.account_id=account1_.id
    and applicati0_.involved_account_id=account2_.id
    and 1=1
    and (
        upper(account1_.name) like ?
        or upper(account2_.id) like ?
    )

这是条件作为表达式失败的地方 applicati0_.account_id=account1_.id and applicati0_.involved_account_id=account2_.id使用and而不是or

Answer 1

按照评论中的建议使用join。

我目前无法测试，但是这样的方法应该可以工作：

CriteriaQuery<Application> query = cb.createQuery(Application.class);
Root<Application> root = query.from(Application.class);
Join<Application, Account> account = root.join("account");
Join<Application, Account> involvedAccount = root.join("involvedAccount");

Predicate conditions = cb.conjunction();

conditions = cb.and(conditions, cb.or(
    cb.like(
        cb.upper(account.get("name")), 
        accountName.toUpperCase()
    ), cb.like(
        cb.upper(involvedAccount.get("name")), 
        accountName.toUpperCase())
    )
);

query.where(conditions);
query.select(root);

具有路径导航的相关实体的JPA标准或条件

1 个答案: