如何在React-native中使用其他应用程序?

时间:2018-09-27 17:22:41

标签: javascript android reactjs react-native

我的应用程序中需要具有类似于Facebook Messenger聊天头的功能,基本上是一个可以在其他应用程序上查看的气泡。除了this问题之外,我在此主题上找不到任何在线内容。那么,有什么办法可以用RN做类似的事情?

1 个答案:

答案 0 :(得分:1)

此功能不直接由react native支持,并且ios中也不支持,因此只有您可以在android中使用Java本机代码实现。为此,您应该在android中编写一个处理此元素生命周期的服务。 您可以在android项目中找到here的简单实现。这是一个简单明了的示例,您可以将其服务用于您的react native项目,只需更改其xml文件以自定义视图即可。 而且,要启动您的服务,您必须编写一个非常简单的react native模块,像这样

@ReactMethod
public void startService(Promise promise) {

    String result = "Success";
    Activity activity = getCurrentActivity();
    if (activity != null) {
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M && !Settings.canDrawOverlays(getReactApplicationContext())) {
            Intent intent = new Intent(Settings.ACTION_MANAGE_OVERLAY_PERMISSION,
                    Uri.parse("package:" + getCurrentActivity().getPackageName()));
            getCurrentActivity().startActivityForResult(intent, MainActivity.DRAW_OVER_OTHER_APP_PERMISSION_REQUEST_CODE);
        }
    }
    try {
        Intent intent = new Intent(FloatingWidgetService.FLOATING_WIDGET_ID);
        intent.setClass(this.getReactApplicationContext(), FloatingWidgetService.class);
        getReactApplicationContext().startService(intent);
        FloatingWidgetService.setUri(uri);
    } catch (Exception e) {
        promise.reject(e);
        return;
    }
    promise.resolve(result);
}

在Android-8Oreo中,您必须要求canDrawOverlays,然后才能像这样在MainActivity中等待结果:

private static final int DRAW_OVER_OTHER_APP_PERMISSION_REQUEST_CODE = 1222;
....
private void startFloatingWidgetService() {
    if (!mStarted) {
        Intent intent = new Intent(this, FloatingWidgetService.class);
        ContextCompat.startForegroundService(this, intent);
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
            this.startForegroundService(intent);
        }else{
            startService(intent);
        }
        mStarted = true;
        finish();
    }
}
....
 @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        if (requestCode == DRAW_OVER_OTHER_APP_PERMISSION_REQUEST_CODE) {
            //Check if the permission is granted or not.
            if (resultCode == RESULT_OK)
                //If permission granted start floating widget service
                startFloatingWidgetService();
            else
                //Permission is not available then display toast
                Toast.makeText(this,
                        getResources().getString(R.string.draw_other_app_permission_denied),
                        Toast.LENGTH_SHORT).show();

        } else {
            super.onActivityResult(requestCode, resultCode, data);
        }
    }

然后,以相同的appstate从该服务再次返回到您的应用(不创建新活动),首先将您的活动启动模式定义为清单中的singleInstance:

<activity
        ...
        android:launchMode="singleInstance"
        ...
        >

并在您的服务中使用这种intent(!):

ReactApplicationContext reactContext = VideoViewModule.getReactContext();
Intent activityIntent = createSingleInstanceIntent();
reactContext.startActivity(activityIntent);



 private Intent createSingleInstanceIntent() {
        ReactApplicationContext reactContext = VideoViewModule.getReactContext();
        String packageName = reactContext.getPackageName();
        Intent launchIntent = reactContext.getPackageManager().getLaunchIntentForPackage(packageName);
        String className = launchIntent.getComponent().getClassName();
        Intent activityIntent = null;
        try {

            Class<?> activityClass = Class.forName(className);

            activityIntent = new Intent(reactContext, activityClass);

            activityIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);

        } catch (Exception e) {
            stopCurrentService();
            Log.e("POIFOIWEGBF", "Class not found", e);

        }
        return activityIntent;
    }

希望对您有帮助。