Question

我想将Observable对象转换为json对象

ObjectMapper mapper = new ObjectMapper();
    Observable<String> response = accountSearchService.searchAccount(paramMap, "", 0, 1);
    mapper.disable(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES);
    AccountSearchResult resultDto = mapper.convertValue(response.subscribe().toString(), AccountSearchResult.class);

这是我要尝试的操作，但遇到OnErrorNotImplementedException。请有人帮我。

Answer 1

subscribe()方法不会返回订阅的实际值，它只会触发对该可观察对象的订阅。相反，您必须“收听”订阅并在完成后进行操作。像这样：

ObjectMapper mapper = new ObjectMapper();
    Observable<String> response = accountSearchService.searchAccount(paramMap, "", 0, 1);
    mapper.disable(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES);

    response.subscribe(stringValue -> {
            AccountSearchResult resultDto = mapper.convertValue(stringValue, AccountSearchResult.class);
        }, throwable -> {
            //onError
        });

如何将Observable <string>转换为JSON

1 个答案: