Question

我有一个字符串如下

const example = ' ( some string ()() here )   ';

如果我用

修剪字符串

example.trim()

它将给我输出：( some string ()() here )

但是我想要输出some string ()() here。如何实现？

const example = ' ( some string ()() here )   ';
console.log(example.trim());

Answer 1

您可以将正则表达式用于开头和结尾的空格/括号：

<C-A/X>

/^\s+\(\s+(.*)\s+\)\s+$/g

如果字符串是可选的前导和/或结尾，则需要创建一些可选的非捕获组

function grabText(str) { 
  return str.replace(/^\s+\(\s+(.*)\s+\)\s+$/g,"$1");
}

var strings = [
  '  ( some (string) here )   ',
  ' ( some string ()() here )   '];
  
strings.forEach(function(str) {
  console.log('>'+str+'<')
  console.log('>'+grabText(str)+'<')
  console.log('-------')
})

/^(?:\s+\(\s+?)?(.*?)(?:\s+\)\s+?)?$/g
/^ - from start
  (?:\s+\(\s+?)? - 0 or more non-capturing occurrences of  ' ( '
                (.*?) - this is the text we want
                     (?:\s+\)\s+?)? - 0 or more non-capturing occurrences of  ' ) '
                                  $/ - till end
                                    g - global flag is not really used here

Answer 2

您可以使用正则表达式获取匹配的字符串，下面的正则表达式匹配第一个字符，后跟字符或空格，并以字母数字字符结尾

const example = ' ( some (string) ()()here )   ';
console.log(example.match(/(\w[\w\s.(.*)]+)\w/g));

Answer 3

如果您要在修剪后仅移除外部支架，则可以使用

var input = ' ( some string ()() here )   '.trim();
if( input.charAt(0) == '(' && input.charAt(input.length-1) == ')') {

var result = input.slice(1, -1).trim()
 console.log(result)
}

最后一个修剪是可选的，它可以删除(和s之间的空格，e和)

Answer 4

class ClassWeights(object):
    """
    Draw random variates for cases when parameter is a dict.
    Should be personalized as needed.
    """
    def __init__(self,y, *args, **kwargs):
        self.class_weights = compute_class_weight("balanced", np.unique(y), y)
        self._make_dists()

    def _make_dists(self):
        self.dist0 = gamma(self.class_weights[0])
        self.dist1 = gamma(self.class_weights[1])

    def rvs(self, *args, **kwargs):
        """override method for drawing random variates"""
        ret_val = { 0: self.dist0.rvs(*args, **kwargs),
                    1: self.dist1.rvs(*args, **kwargs)}
        return ret_val

Answer 5

您可以使用递归方法并指定希望修剪字符串的次数。这也可以用于圆括号以外的其他内容，例如方括号：

const example = ' ( some string ()() here )   ';
const exampleTwo = ' [  This, is [some] text    ]   ';

function trim_factor(str, times) {
  if(times == 0) {
    return str;
  }
  str = str.trim();
  return str.charAt(0) + trim_factor(str.substr(1, str.length-2), times-1) + str.charAt(str.length-1);
}

console.log(trim_factor(example, 2));
console.log(trim_factor(exampleTwo, 2));

如何修剪多个字符？

5 个答案: