Question

我已经查看了该网站的方法，但没有成功。

所以我要遍历两个csv文件，当我到达一个空字符串/单元格时会给我错误：ValueError：int（）的无效文字，基数为10：''

我理解这是什么意思，但这是我尝试过的。

def normalise(students_file, units_list):
    file1 = open(students_file, 'r')
    data1 = file1.readline().splitlines()

    file2 = open(units_list, 'r')
    data2 = file2.read().splitlines()


    for line in data1:
        line = line.split(",")
        for row in data2:
            row = row.split(",")
            for n in range(1, len(row), 2):
                for i in range(1, len(line), 1):
                    if i == '':
                        pass
                    else:
                        print(int(line[i]) / int(row[n]))

我知道这段代码行得通，因为第一个增量的输出是0.6，这是我想要的，但是第二个增量正在尝试对空字符串进行除法，并且因为int（）无法转换空字符串，因此运行错误。

任何解决方案将不胜感激。

Answer 1

            for i in range(1, len(line), 1):
                if i == '':

if不能为True，因为i将为整数。您可能是说if line[i] == '':吗？

另一种方法是使用try块：

try:
     print(int(line[i]) / int(row[n]))
except:
    # do whatever you need to do when cell is empty 
    # or whatever other error occurs, for example division by 0...

Answer 2

就像评论说的那样。

在您的代码中，我认为可能会出现多个潜在问题。

因此，我认为您可能需要检查line[i]和row[n] 我不确定如果它是一个空字符串，你想做什么。

但是我可以解决这个问题，并留下您的反应空间。

def normalise(students_file, units_list):
    file1 = open(students_file, 'r')
    data1 = file1.readline().splitlines()

    file2 = open(units_list, 'r')
    data2 = file2.read().splitlines()

    for line in data1:
        line = line.split(",")
        for row in data2:
            row = row.split(",")
            for n in range(1, len(row), 2):
                for i in range(1, len(line), 1):
                    #if i == '':
                    # i would not be '' because it comes from range()
                        #pass
                    #else:
                        #print(int(line[i]) / int(row[n]))
                    if line[i] == "" or row[n] == "":
                        pass
                        # you could do somethings likes assigning some of them as 0.
                    else:
                        print(int(line[i]) / int(row[n]))

也许它可能不是一个空字符串，也不是一个单词。您可以使用try ...except...

def normalise(students_file, units_list):
    file1 = open(students_file, 'r')
    data1 = file1.readline().splitlines()

    file2 = open(units_list, 'r')
    data2 = file2.read().splitlines()


    for line in data1:
        line = line.split(",")
        for row in data2:
            row = row.split(",")
            for n in range(1, len(row), 2):
                for i in range(1, len(line), 1):
                    try:
                        print(int(line[i]) / int(row[n]))
                    except:
                        print(int(line[i]) / int(row[n]))

如何为空单元格csv文件返回无或为0

2 个答案: