我正在看这篇文章，描述了在POCO属性之间进行数据绑定的简单方法：Data Binding POCO Properties
Bevan的评论之一包括一个简单的Binder类，可用于完成此类数据绑定。它适用于我需要的东西，但我想实施Bevan为改进课程而提出的一些建议，即：
此外，鉴于按字符串指定属性容易出错，您可以使用Linq表达式和扩展方法。然后而不是写
Binder.Bind( source, "Name", target, "Name")
source.Bind( Name => target.Name);
我很确定我可以处理前三个（虽然可以随意包含这些更改）但我不知道如何使用Linq表达式和扩展方法来编写代码而不使用属性名称字符串。
任何提示？
以下是链接中的原始代码：
public static class Binder
{
public static void Bind(
INotifyPropertyChanged source,
string sourcePropertyName,
INotifyPropertyChanged target,
string targetPropertyName)
{
var sourceProperty
= source.GetType().GetProperty(sourcePropertyName);
var targetProperty
= target.GetType().GetProperty(targetPropertyName);
source.PropertyChanged +=
(s, a) =>
{
var sourceValue = sourceProperty.GetValue(source, null);
var targetValue = targetProperty.GetValue(target, null);
if (!Object.Equals(sourceValue, targetValue))
{
targetProperty.SetValue(target, sourceValue, null);
}
};
target.PropertyChanged +=
(s, a) =>
{
var sourceValue = sourceProperty.GetValue(source, null);
var targetValue = targetProperty.GetValue(target, null);
if (!Object.Equals(sourceValue, targetValue))
{
sourceProperty.SetValue(source, targetValue, null);
}
};
}
}
答案 0 :(得分：12)
以下内容将从lambda表达式返回属性名称作为字符串：
public string PropertyName<TProperty>(Expression<Func<TProperty>> property)
{
var lambda = (LambdaExpression)property;
MemberExpression memberExpression;
if (lambda.Body is UnaryExpression)
{
var unaryExpression = (UnaryExpression)lambda.Body;
memberExpression = (MemberExpression)unaryExpression.Operand;
}
else
{
memberExpression = (MemberExpression)lambda.Body;
}
return memberExpression.Member.Name;
}
用法：
public class MyClass
{
public int World { get; set; }
}
...
var c = new MyClass();
Console.WriteLine("Hello {0}", PropertyName(() => c.World));
<强>更新
public static class Extensions
{
public static void Bind<TSourceProperty, TDestinationProperty>(this INotifyPropertyChanged source, Expression<Func<TSourceProperty, TDestinationProperty>> bindExpression)
{
var expressionDetails = GetExpressionDetails<TSourceProperty, TDestinationProperty>(bindExpression);
var sourcePropertyName = expressionDetails.Item1;
var destinationObject = expressionDetails.Item2;
var destinationPropertyName = expressionDetails.Item3;
// Do binding here
Console.WriteLine("{0} {1}", sourcePropertyName, destinationPropertyName);
}
private static Tuple<string, INotifyPropertyChanged, string> GetExpressionDetails<TSourceProperty, TDestinationProperty>(Expression<Func<TSourceProperty, TDestinationProperty>> bindExpression)
{
var lambda = (LambdaExpression)bindExpression;
ParameterExpression sourceExpression = lambda.Parameters.FirstOrDefault();
MemberExpression destinationExpression = (MemberExpression)lambda.Body;
var memberExpression = destinationExpression.Expression as MemberExpression;
var constantExpression = memberExpression.Expression as ConstantExpression;
var fieldInfo = memberExpression.Member as FieldInfo;
var destinationObject = fieldInfo.GetValue(constantExpression.Value) as INotifyPropertyChanged;
return new Tuple<string, INotifyPropertyChanged, string>(sourceExpression.Name, destinationObject, destinationExpression.Member.Name);
}
}
用法：
public class TestSource : INotifyPropertyChanged
{
public event PropertyChangedEventHandler PropertyChanged;
public string Name { get; set; }
}
public class TestDestination : INotifyPropertyChanged
{
public event PropertyChangedEventHandler PropertyChanged;
public string Id { get; set; }
}
class Program
{
static void Main(string[] args)
{
var x = new TestSource();
var y = new TestDestination();
x.Bind<string, string>(Name => y.Id);
}
}
答案 1 :(得分：1)
此问题非常类似于：Retrieving Property name from lambda expression
（来自https://stackoverflow.com/a/17220748/1037948的交叉发布回复）
我不知道你是否需要绑定到“subproperties”，但检查lambda.Body Member.Name只会返回“final”属性，而不是“完全限定”属性。
ex）o => o.Thing1.Thing2会产生Thing2，而非Thing1.Thing2。
尝试使用此方法简化具有表达式重载的EntityFramework DbSet.Include(string)时，这是有问题的。
所以你可以“欺骗”并解析Expression.ToString。在我的测试中，性能似乎相当，所以如果这是一个坏主意，请纠正我。
/// <summary>
/// Given an expression, extract the listed property name; similar to reflection but with familiar LINQ+lambdas. Technique @via https://stackoverflow.com/a/16647343/1037948
/// </summary>
/// <remarks>Cheats and uses the tostring output -- Should consult performance differences</remarks>
/// <typeparam name="TModel">the model type to extract property names</typeparam>
/// <typeparam name="TValue">the value type of the expected property</typeparam>
/// <param name="propertySelector">expression that just selects a model property to be turned into a string</param>
/// <param name="delimiter">Expression toString delimiter to split from lambda param</param>
/// <param name="endTrim">Sometimes the Expression toString contains a method call, something like "Convert(x)", so we need to strip the closing part from the end</pa ram >
/// <returns>indicated property name</returns>
public static string GetPropertyName<TModel, TValue>(this Expression<Func<TModel, TValue>> propertySelector, char delimiter = '.', char endTrim = ')') {
var asString = propertySelector.ToString(); // gives you: "o => o.Whatever"
var firstDelim = asString.IndexOf(delimiter); // make sure there is a beginning property indicator; the "." in "o.Whatever" -- this may not be necessary?
return firstDelim < 0
? asString
: asString.Substring(firstDelim+1).TrimEnd(endTrim);
}//-- fn GetPropertyNameExtended
（检查分隔符可能有点矫枉过正）
答案 2 :(得分：0)
这可能超出或不完全符合您的要求，但我已经做了类似的事情来处理两个对象之间的属性映射：
public interface IModelViewPropagationItem<M, V>
where M : BaseModel
where V : IView
{
void SyncToView(M model, V view);
void SyncToModel(M model, V view);
}
public class ModelViewPropagationItem<M, V, T> : IModelViewPropagationItem<M, V>
where M : BaseModel
where V : IView
{
private delegate void VoidDelegate();
public Func<M, T> ModelValueGetter { get; private set; }
public Action<M, T> ModelValueSetter { get; private set; }
public Func<V, T> ViewValueGetter { get; private set; }
public Action<V, T> ViewValueSetter { get; private set; }
public ModelViewPropagationItem(Func<M, T> modelValueGetter, Action<V, T> viewValueSetter)
: this(modelValueGetter, null, null, viewValueSetter)
{ }
public ModelViewPropagationItem(Action<M, T> modelValueSetter, Func<V, T> viewValueGetter)
: this(null, modelValueSetter, viewValueGetter, null)
{ }
public ModelViewPropagationItem(Func<M, T> modelValueGetter, Action<M, T> modelValueSetter, Func<V, T> viewValueGetter, Action<V, T> viewValueSetter)
{
this.ModelValueGetter = modelValueGetter;
this.ModelValueSetter = modelValueSetter;
this.ViewValueGetter = viewValueGetter;
this.ViewValueSetter = viewValueSetter;
}
public void SyncToView(M model, V view)
{
if (this.ViewValueSetter == null || this.ModelValueGetter == null)
throw new InvalidOperationException("Syncing to View is not supported for this instance.");
this.ViewValueSetter(view, this.ModelValueGetter(model));
}
public void SyncToModel(M model, V view)
{
if (this.ModelValueSetter == null || this.ViewValueGetter == null)
throw new InvalidOperationException("Syncing to Model is not supported for this instance.");
this.ModelValueSetter(model, this.ViewValueGetter(view));
}
}
这允许您创建此对象的实例，然后使用“SyncToModel”和“SyncToView”来回移动值。下面的内容允许您对这些内容进行分组，并通过一次调用来回移动数据：
public class ModelViewPropagationGroup<M, V> : List<IModelViewPropagationItem<M, V>>
where M : BaseModel
where V : IView
{
public ModelViewPropagationGroup(params IModelViewPropagationItem<M, V>[] items)
{
this.AddRange(items);
}
public void SyncAllToView(M model, V view)
{
this.ForEach(o => o.SyncToView(model, view));
}
public void SyncAllToModel(M model, V view)
{
this.ForEach(o => o.SyncToModel(model, view));
}
}
用法看起来像这样：
private static readonly ModelViewPropagationItem<LoginModel, ILoginView, string> UsernamePI = new ModelViewPropagationItem<LoginModel, ILoginView, string>(m => m.Username.Value, (m, x) => m.Username.Value = x, v => v.Username, (v, x) => v.Username = x);
private static readonly ModelViewPropagationItem<LoginModel, ILoginView, string> PasswordPI = new ModelViewPropagationItem<LoginModel, ILoginView, string>(m => m.Password.Value, (m, x) => m.Password.Value = x, v => v.Password, (v, x) => v.Password = x);
private static readonly ModelViewPropagationGroup<LoginModel, ILoginView> GeneralPG = new ModelViewPropagationGroup<LoginModel, ILoginView>(UsernamePI, PasswordPI);
public UserPrincipal Login_Click()
{
GeneralPG.SyncAllToModel(this.Model, this.View);
return this.Model.DoLogin();
}
希望这有帮助！
答案 3 :(得分：0)
var pr = typeof（CCategory）.GetProperties（）。选择（i =＆gt; i.Name）.ToList（）; ;
答案 4 :(得分：0)
声明：
class Foo<T> {
public string Bar<T, TResult>(Expression<Func<T, TResult>> expersion)
{
var lambda = (LambdaExpression)expersion;
MemberExpression memberExpression;
if (lambda.Body is UnaryExpression)
{
var unaryExpression = (UnaryExpression)lambda.Body;
memberExpression = (MemberExpression)unaryExpression.Operand;
}
else
{
memberExpression = (MemberExpression)lambda.Body;
}
return memberExpression.Member.Name;
}
}
用法：
var foo = new Foo<DummyType>();
var propName = foo.Bar(d=>d.DummyProperty)
Console.WriteLine(propName); //write "DummyProperty" string in shell