我正在尝试创建一个可以访问我的数据库的firebase函数。但是,当我运行 firebase deploy --only函数时,出现以下错误:
TypeError: firebase.initializeApp is not a function
at Object.<anonymous> (C:\Users\xxx\Documents\TriviaGame\functions\index.js:34:10)
at Module._compile (module.js:653:30)
at Object.Module._extensions..js (module.js:664:10)
at Module.load (module.js:566:32)
at tryModuleLoad (module.js:506:12)
at Function.Module._load (module.js:498:3)
at Module.require (module.js:597:17)
at require (internal/module.js:11:18)
at C:\Users\xxx\AppData\Roaming\npm\node_modules\firebase-tools\lib\triggerParser.js:21:11
at Object.<anonymous> (C:\Users\xxx\AppData\Roaming\npm\node_modules\firebase-tools\lib\triggerParser.js:75:3)
这是我的代码:
'use strict';
var firebase = require('firebase');
const {actionssdk} = require('actions-on-google');
const functions = require('firebase-functions');
const app = actionssdk({debug: true});
var config = {
apiKey: "",
authDomain: "",
databaseURL: "",
projectId: "",
storageBucket: "",
messagingSenderId: ""
};
firebase.initializeApp(config);
var database=firebase.database();
var allMyStuff = database.ref('triviagame');
//do stuff with my database values
答案 0 :(得分:1)
npm install firebase
在我的函数目录中,更新了我的软件包,并允许我访问initializeApp()
函数。