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Question

连续出现的字符数，然后是字符

外部输入：'zzzyyyyxxxwwvzz'

预期输出：“ 3z4y3x2w1v2z”

我尝试过的代码

<?php
$str = "zzzyyyyxxxwwvzz";
$strArray = count_chars($str,1);

foreach ($strArray as $key=>$value)
   {
   echo $value.chr($key);
   }
?>

输出为：5z4y3x2w1v

Answer 1

使用str_split函数，获取数组中给定字符串中的所有字符
现在，使用基本循环和条件并存储前一个字符，您可以确定是否连续，并相应地生成生成的输出字符串。

尝试以下操作（在代码注释中进行解释）：

$input = 'zzzyyyyxxxwwvzz';

// Split full string into array of single characters
$input_chars = str_split($input);

// initialize some temp variables
$prev_char = '';
$consecutive_count = 0;

$output = '';

// Loop over the characters
foreach ($input_chars as $char) {

    // first time initialize the previous character
    if ( empty($prev_char) ) {
        $prev_char = $char;
        $consecutive_count++;
    } elseif ($prev_char === $char) { // current character matches previous character
        $consecutive_count++;
    } else { // not consecutive character
        // add to output string
        $output .= ($consecutive_count . $prev_char);

        // set current char as new previous_char
        $prev_char = $char;
        $consecutive_count = 1;
    }
}

// handle remaining characters
$output .= ($consecutive_count . $prev_char);
echo $output;

连续出现字符

1 个答案:

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