Question

在打字稿中，我有两个数组：

var StarWarsChars: any = [
      "Jedi Yoda",
      "Jedi Mace Windu",
      "Jedi Qui-Gon Jinn",
      "Jedi Qui-Gon Jinn",
      "Jedi Obi-Wan Kenobi",
      "Sith Count Dooku",
      "Sith Darth Sidious",
      "Droid R2-D2",
      "Droid R2-D2",
      "Droid C-3PO",
      "Droid BB-8"
    ];

var StarWarsFilter: any = ["Jedi", "Sith"];

，我希望创建一个由StarWarsChars数组中的值组成的第三个数组，其中值包含StarWarsFilter中的值。我知道如何根据单个值进行过滤：

var StarWarsFiltered = StarWarsChars.filter(e =>
      e.includes(StarWarsFilter[0])
    );

返回：

0: "Jedi Yoda"
1: "Jedi Mace Windu"
2: "Jedi Qui-Gon Jinn"
3: "Jedi Qui-Gon Jinn"
4: "Jedi Obi-Wan Kenobi"

但是我不知道如何对StarWarsFilter中的所有值执行此过滤器。我可以尝试循环，但我想有一种更好的方法。

Answer 1

首先，我建议为您的数组使用正确的类型：string[]

您应该能够执行以下操作：

var StarWarsChars: string[] = [
  "Jedi Yoda",
  "Jedi Mace Windu",
  "Jedi Qui-Gon Jinn",
  "Jedi Qui-Gon Jinn",
  "Jedi Obi-Wan Kenobi",
  "Sith Count Dooku",
  "Sith Darth Sidious",
  "Droid R2-D2",
  "Droid R2-D2",
  "Droid C-3PO",
  "Droid BB-8"
];

var StarWarsFilter: string[] = ["Jedi", "Sith"];

var StarWarsFiltered = StarWarsChars.filter(e =>
      StarWarsFilter.some(f => e.includes(f))
);

Answer 2

const StarWarsFiltered = StarWarsChars.filter(x => x.split(' ').some(y => StarWarsFilter.includes(y)));

这将返回StarWarsChars中所有在StarWarsFilter中包含单词的项

过滤一个数组，其中第一个数组中的值包含第二个数组中的打字稿

2 个答案: