Question

我正在创建一个简单的联系表。我的自定义类型以这种方式开始：

<?php

namespace MyCompany\AppBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;
use Symfony\Component\Form\Extension\Core\Type\TextType;
use Symfony\Component\Form\Extension\Core\Type\TextareaType;
use Symfony\Component\Form\Extension\Core\Type\EmailType;
use Symfony\Component\Validator\Constraints\Email;
use Symfony\Component\Validator\Constraints\NotBlank;

class ContactType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {

...并且我的控制器以这种方式启动：

<?php

namespace MyCompany\AppBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Request;

class ContactController extends Controller
{
    public function contactAction(Request $request)
    {
        // Create the form according to the FormType created previously.
        // And give the proper parameters
        $form = $this->createForm('MyCompany\AppBundle\Form\ContactType',null,array(
            // To set the action use $this->generateUrl('route_identifier')
            'action' => $this->generateUrl('myapplication_contact'),
            'method' => 'POST'
        ));

...但是我发现我的应用程序无法加载类型。我收到以下异常消息：

无法加载类型“ MyCompany \ AppBundle \ Form \ ContactType” 500内部服务器错误-InvalidArgumentException

我该怎么做才能开始调试呢？

Answer 1

由于您使用的是Symfony 2.7，因此使用表单类型类在控制器中创建表单的正确方法是：

<?php

namespace MyCompany\AppBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Request;

use MyCompany\AppBundle\Form\ContactType; // add this

class ContactController extends Controller
{
    public function contactAction(Request $request)
    {
        // Create the form according to the FormType created previously.
        // And give the proper parameters
        $form = $this->createForm(new ContactType(), null, array(
            // To set the action use $this->generateUrl('route_identifier')
            'action' => $this->generateUrl('myapplication_contact'),
            'method' => 'POST'
        ));

请参阅symfony documentation

Answer 2

在Symfony 2.7中，您必须在$this->createForm

中发送类似的实例

new MyCompany\AppBundle\Form\ContactType

Symfony 2.7：无法加载类型

2 个答案: