Question

我在python 3中编写了一个代码，其中包括用于查找数字的二进制serach算法。用户将输入0,1或2作为更高或更低的点。因此，我使用以下代码：

def guess():
    i = 0
    # i is the lowest number in range of possible guess
    j = 100
    # j is the highest number in range of possible guesses
    m = 50
    # m is the middle number in range of possible guesses
    counter = 1
    # counter is the number of guesses take.
    print ("Please guess a number")
     condition = input("Is your guess " + str(m) + "? (0 means it's 
     too low, 1 means it's your guess and 2 means it's too high) ")
    while condition != 1:
         counter += 1
         if condition == 0:
            i = m + 1
         elif condition == 2:
              j = m - 1
         m = (i + j)//2
         condition = input("Is your guess " + str(m) + "? (0 means 
         it's too low, 1 means it's your guess and 2 means it's too 
          high) ")
     print ("It took" , counter , "times to guess your number")
guess()

好的，我运行后，输出如下：

Please guess a number
Is your guess 50? (0 means it's too low, 1 means it's your guess and 2 means 
it's too high) 0

当我输入0

Is your guess 50.0? (0 means it's too low, 1 means it's your guess and 2 
means it's too high)

它的结果始终为50.0，但应低于50。有什么办法可以减少程序中的数字。谢谢！

Answer 1

您需要将输入转换为整数，它将输入作为字符串读取。

condition = int(input("Is your guess " + str(m) + "? (0 means it's 
    too low, 1 means it's your guess and 2 means it's too high) ").strip())

通过strip，它将在将字符串转换为整数之前负责删除空格和换行符。

Answer 2

在Python 3中，input()将始终返回字符串。因此，诸如condition == 0或condition == 2之类的比较将始终返回false。

相反，请尝试检查condition == '0'或condition == '2'。更一般而言，您可能应该考虑用户可能输入了0、1或2以外的内容并显示错误消息。那本可以帮助您捕获此错误！

在Python 3中找到用户输入的猜测数字

2 个答案: