BATCH SCRIPT：删除文件中包含特定字符的行

Question

我正在尝试删除文件中所有包含某些值的所有行。 我的文件如下所示：

"BLOT"  "GL.AC" "00350" "AMG"   "10502" "     " "                    "  "     " "     " "     " "     " "
"ACOD"  "BC.FF" "00350" "AMG"   "10502" "     " "                    "  "     " "     " "     " "     " "
"VARC"  "DF.RR" "00350" "AMG"   "10502" "     " "                    "  "     " "     " "     " "     " "

想法是删除所有包含字符串“ BLOT”和“ VARC”的行

预期结果是：

"ACOD"  "BC.FF" "00350" "AMG"   "10502" "     " "                    "  "     " "     " "     " "     " "

我们如何使用批处理脚本从文件中删除这些行？

我找到了此命令，但这不会删除行

powershell -Command "(gc C:\TEST_AUTO.txt) -replace 'BLOT', 'XXXX' | Out-File myFile.txt"

感谢您的帮助

Answer 1

最好使用aschipfl所提示的FindStr命令：

FindStr /V "^\"BLOT\" ^\"VARC\"" "C:\TEST_AUTO.txt">"myfile.txt"

您是否希望使用批处理文件PowerShell选项？

PowerShell "GC 'C:\TEST_AUTO.txt'|?{$_ -NotMatch '^\"BLOT\"|^\"VARC\"'}|SC 'myfile.txt'"

Answer 2

问题由usind解决：

查找/ V“ BLOT” C：\ TEST_AUTO.txt> result.txt