Question

一般来说，我真的是sql / stackoverflow的新手，所以请多多包涵。

我有一个独特的选择查询，它返回以下结果

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
  <div class="full-width">
    <iframe class="video-iframe fullsize"></iframe>
    <a href="#section2">
      <span class="dot">
            <i class="arrow-down"></i>
          </span>
    </a>
  </div>
  <div class="half-width" id="section2">
    <div class="half-width-content">
      <h1></h1>
      <div class="half-width-text">

        <div class="text-content">
          <p>
          </p>
        </div>
      </div>
    </div>
  </div>
  <div class="half-width">
    <div class="half-width-content">
      <div class="instagram-slideshow" id="1">
        <img class="slide">
      </div>
    </div>
  </div>
  <div class="half-width section3">
    <div class="half-width-content">
      <div class="instagram-slideshow" id="2">
        <img class="slide">
      </div>
    </div>
  </div>
  <div class="half-width section3">
    <div class="half-width-content">
      <div class="middle-text">
        <h2></h2>
        <p></p>
        <div class="list-div">
          <ul class="items-list" id="list">
            <li></li>
            <li></li>
            <li></li>
            <li></li>
          </ul>
        </div>
        <img class="hand-writing-img">
      </div>
    </div>
  </div>
  <div class="full-width section3">
    <div class="content">
      <div class="third-parent">
        <div class="third" id="one">
          <img>
        </div>
        <div class="third" id="two">
          <div class="middle-text">
            <h1></h1>
            <div class="list-div2">
              <ul class="items-list2" id="list">
                <li></li>
                <li></li>
                <li></li>
                <li></li>
              </ul>
            </div>
          </div>
        </div>
        <div class="third" id="three">
          <img>
        </div>
      </div>
    </div>
  </div>
</div>

因此，显然每个查询将具有不同的名称。我想展示的是如果第一人称和第二人称只有一行，如果它的ID为0，则想显示一条完成的消息；如果它的1->不完整，并且它们有2行（0和1），我想显示工作消息。 / p>

Name  Surname  Name2  Surname2  Status
----  -------  -----  --------  ------
Peter  Parker  Mary     Jane       0
Peter  Parker  Felicia  Hardy      1
Peter  Parker  Felicia  Hardy      0
Peter  Parker  Jonah   Jameson     1

我该怎么办？

Answer 1

使用汇总功能时的用例

    select Name,Surname,Name2,Surname2,
case when count( distinct Status) = 2 then 
         'Working' when sum(Status)=0 then 'Finished' else 'Incomplete'

       end  as status 
  from t
group by Name, Surname, Name2, Surname2;


NAME    SURNAME     NAME2   SURNAME2    STATUS
Peter   Parker      Mary    Jane         Finished
Peter   Parker      Felicia Hardy        Working
Peter   Parker     Jonah    Jameson      Incomplete

Answer 2

您可以使用此

SELECT name, surname, name2, surname2, 
    CASE 
        WHEN COUNT(DISTINCT status) = 2 THEN 'Working'
        WHEN MAX(status) = 1 THEN 'Incomplete' 
        WHEN MAX(status) = 0 THEN 'Finished'
    END AS status
FROM table_name
--WHERE status IN (0, 1)
GROUP BY name, surname, name2, surname2
ORDER BY name, surname, name2, surname2;

或者这个：

SELECT name, surname, name2, surname2, 
    CASE
        WHEN MIN(status) = 1 THEN 'Incomplete' 
        WHEN MAX(status) = 0 THEN 'Finished'
        ELSE 'Working'
    END AS status
FROM table_name
WHERE status IN (0, 1)
GROUP BY name, surname, name2, surname2
ORDER BY name, surname, name2, surname2;

如果您只有两个状态0和1，则省略WHERE子句

Answer 3

您可以将group by Name, Surname, Name2, Surname2与avg(status)选项一起使用

select Name, Surname, Name2, Surname2, 
       ( case when avg(Status) = 1 then 
         'Incomplete'
         when avg(Status) = 0 then
         'Finished'
         else
         'Working'
       end ) as status 
  from tab
group by Name, Surname, Name2, Surname2;

SQL Fiddle Demo

SQL条件检查行元素

3 个答案: