Question

我正在尝试按时间值组合多个数组。我有这样的数组。我想合并2个数组，我使用array_merge

Array_one :   
     [
           {
              date:"2018-06-23",
              size:"L",
              type:"shoes",
              value_one:"66"
           },
          {
              date:"2018-06-23",
              size:"XL",
              type:"shirt",
              value_one:"43"
           },
          {
              date:"2018-06-23",
              size:"M",
              type:"Bag",
              value_one:"23"
           }
        ]


Array_two :
[
   {
      date:"2018-06-23",
      size:"L",
      type:"shoes",
      value_two:"28"
   },
  {
      date:"2018-06-23",
      size:"XL",
      type:"shirt",
      value_two:"56"
   },
  {
      date:"2018-06-23",
      size:"M",
      type:"Bag",
      value_two:"14"
   },
  {
      date:"2018-06-23",
      size:"S",
      type:"Cap",
      value_two:"29"
   }
]

如果索引日期，大小相同，则需要将这2个数组与y值合并，然后键入其合并。例如合并后的数组应该是这样的。

Array_final :
    [
           {
              date:"2018-06-23",
              size:"L",
              type:"shoes",
              value_one:"66",
              value_two:"28"
           },
          {
              date:"2018-06-23",
              size:"XL",
              type:"shirt",
              value_one:"43",
              value_two:"56"
           },
          {
              date:"2018-06-23",
              size:"M",
              type:"Bag",
              value_one:"23",
              value_two:"14"
           },
           {
              date:"2018-06-23",
              size:"S",
              type:"Cap",
              value_one:"null",
              value_two:"29"
           }
        ]

在这种情况下我该怎么办？我想用php，laravel或集合“ Laravel”类解决这种情况。请帮助我。

Answer 1

您可以尝试

$Array_final= [];
foreach ($Array_one as $key1 => $value1) {
    foreach ($Array_two as $key2 => $value2) {
        if ($value1['date']==$value2['date']) {
            $Array_final[]=$value2+$value1;
        }
    }
}

Answer 2

尝试

    //both arrays will be merged including duplicates
    $result = array_merge( $array1, $array2 );
    //duplicate objects will be removed
    $result = array_map("unserialize", array_unique(array_map("serialize", $result)));
    //array is sorted on the bases of id
    sort( $result );

Answer 3

尝试

var result = a1.slice(0);

for (var i = 0 ; i < result.length ; i++){
  for (var j = 0; j < a2.length ; j++){
    if (result[i]. date == a2[j]. date && result[i]. size == a2[j]. size && result[i]. type == a2[j]. type){
      result[i]. value_one = a2[j]. value_one;
      result[i]. value_two = a2[j].value_two;
    }
  };  
};
console.log(result);

Answer 4

您可以尝试以下方法：-

$final = $arr1; // default get all values from first array
foreach ($arr2 as $value) { // loop through second array to match
    $flag = 0;
    foreach ($final as $key => $data) {
        // Check for date, size and type
        if ($data['date']===$value['date'] && $data['size']===$value['size'] && $data['type']===$value['type']) {
            $final[$key]['value_two'] = $value['value_two'];
            $flag = 1;
            break;
        }
    }
    if ($flag === 0) { // If similar not found, then add new one
        array_push($final, $value);
    }
}
print_r($final);

输出：-

Array
(
    [0] => Array
        (
            [date] => 2018-06-23
            [size] => L
            [type] => shoes
            [value_one] => 66
            [value_two] => 28
        )

    [1] => Array
        (
            [date] => 2018-06-23
            [size] => XL
            [type] => shirt
            [value_one] => 43
            [value_two] => 56
        )

    [2] => Array
        (
            [date] => 2018-06-23
            [size] => M
            [type] => Bag
            [value_one] => 23
            [value_two] => 14
        )

    [3] => Array
        (
            [date] => 2018-06-23
            [size] => S
            [type] => Cap
            [value_two] => 29
        )

)

小提琴链接：-https://3v4l.org/fSh1V

我想合并数组，如果相同的值

4 个答案: