Akka http建筑Uri

Question

我正在尝试构建Uri，但是Query方法会给我类型不匹配，预期的字符串，实际的Uri.Query

def buildUri(url: String, query: Option[Map[String, String]] = None): Uri = {

    val fullUrl = endpoint + (if (endpoint.endsWith("/")) url else "/" + url)

    val uri: Uri = query match {
      case Some(map) if map.nonEmpty =>
        Uri(fullUrl.toString).copy(query = Query(map))
      case _ =>
        Uri(fullUrl.toString)
    }

    uri

  }

Answer 1

我想这就是你想要做的：

def buildUri(url: String, query: Option[Map[String, String]] = None): Uri = {

    val fullUrl = endpoint + (if (endpoint.endsWith("/")) url else "/" + url)

    val uri: Uri = query match {
      case Some(map) if map.nonEmpty =>
        Uri(fullUrl.toString).withQuery(query = Query(map))
      case _ =>
        Uri(fullUrl.toString)
    }

    uri
  }