HTML:
<section class="cd-gallery">
<ul id="courses">
</ul>
<div class="cd-fail-message">No results found</div>
</section>
<ul>
<li><input id="buttonaz" type="button" value="Course name(a-z)"/></li>
<li><input id="buttonza" type="button" value="Course name(z-a)"/></li>
<li><input id="buttonlu" type="button" value="Last updated"></li>
<ul>
JavaScript:
var public_spreadsheet_url = 'https://docs.google.com/spreadsheets/..."
function init() {
Tabletop.init( { key: public_spreadsheet_url,
callback: showInfo,
simpleSheet: true } );
}
window.addEventListener('DOMContentLoaded', init);
function sortAZ(a, b) {
var x = a.Course.toLowerCase();
var y = b.Course.toLowerCase();
return ((x < y) ? -1 : ((x > y) ? 1 : 0));
}
function sortZA(a, b) {
var x = a.Course.toLowerCase();
var y = b.Course.toLowerCase();
return ((x > y) ? -1 : ((x < y) ? 1 : 0));
}
function showInfo(data) {
var bodyContent = '';
var sheetUrlRoot = 'https://docs.google.com/spreadsheets/d/';
var buttonaz = document.getElementById("buttonaz");
var buttonza = document.getElementById("buttonza");
console.log(data)
for (var i = 0; i < data.length; i++) {
var sheetUrl = sheetUrlRoot + data[i].ActionId;
var c = data[i].Course;
var courseName = '<div class=\"courseName\">' + c + '</div>';
var designer = data[i]['Designer'].toLowerCase();
var numHolds = data[i]['On Hold']
if (numHolds > 0) {
bodyContent += '<li class="color-2 course mix ' + designer + ' "style="background-color: #E89696";>' + courseName + statusList+ sheetLink+ '</li>';
} else if (numHolds <= 0){
bodyContent += '<li class="color-1 course mix ' + designer + ' "style="background-color: #C2D5BE";>' + courseName + statusList+ sheetLink+'</li>';
}
}
document.getElementById('courses').innerHTML = bodyContent;
document.getElementById('buttonaz').onclick = data.sort(sortAZ);
document.getElementById('buttonaz').onclick = data.sort(sortZA);
}
Hi Stack Overflow用户, 我已使用tabletop.js导入数据以显示我的大学手头的一组课程。但是,当单击按钮“课程名称(a-z)”和“课程名称(z-a)”时,我无法显示按字母顺序从a-z以及从z-a排序的课程。首次加载页面时显示数据,但是单击排序按钮时不会执行任何操作。
请帮助,我们将不胜感激!
P.S。我还使用mixitup jQuery插件按设计者的名称过滤课程。
答案 0 :(得分:1)
请参阅具有两个按钮的代码,一个用于排序aZ,另一个用于排序Za。点击展开代码段,您将看到两个按钮,点击它们并享受排序
cols = 3
seps = ' ' * (cols - 1) + '\n'
with open("output.txt", "w") as f:
for i, (k, v) in enumerate(dict_cols.items()):
sep = '' if i == len(dict_cols) - 1 else ',' + seps[i % cols]
f.write(v + sep)
如果传入数据是数组,请使用内置于sort()函数的javascript对数据进行排序
<!DOCTYPE html>
<html>
<body>
<h2>JavaScript Array Sort</h2>
<p>Click the buttons to sort the array alphabetically or numerically.</p>
<button onclick="myFunction1()">Sort Az</button>
<button onclick="myFunction2()">Sort zA</button>
<p id="demo"></p>
<script>
var points = ["z", "b", "d", "a"];
var data1=Array.prototype.slice.call(points);
console.log('Za Sort ',data1.sort().reverse());
document.getElementById("demo").innerHTML = points;
function myFunction1() {
points.sort();
document.getElementById("demo").innerHTML = points;
}
function myFunction2() {
document.getElementById("demo").innerHTML = data1.sort().reverse();
}
</script>
</body>
</html>
答案 1 :(得分:0)
这是在javascript中对某些数组进行排序的函数,具体取决于您如何应用它,并考虑到代码段:
//Sort alphabetically and ascending:
var myarray=["Bob", "Bully", "Amy"];
myarray.sort();
// Array now becomes ["Amy", "Bob", "Bully"]
现在让我们做相反的事情:
///按字母顺序和降序排列:
var myarray = [“ Bob”,“ Bully”,“ Amy”]
myarray.sort()
myarray.reverse()//数组现在变为[“ Bully”,“ Bob”,“ Amy”]
答案 2 :(得分:0)
如果您要使用库https://underscorejs.org/#
var stooges = [{name: 'moe', age: 40}, {name: 'larry', age: 50}, {name: 'curly', age: 60}];
_.sortBy(stooges, 'name');