Question

我编写了一个用于调用Google Places API的函数，但我想做得更好。具体来说，我怀疑在函数调用中有更好的方法来处理可选参数，例如location和radius。如何在不编写可选参数的所有可能排列的情况下动态构造自己的url？

def get_data(query,api_key,radius=None,location=None):
    if location==None and radius==None:
    url="https://maps.googleapis.com/maps/api/place/textsearch/json?query=%s&fields=name,formatted_address,opening_hours,price_level,rating&key=%s" % (query,api_key)
    elif location is not None:
    url="https://maps.googleapis.com/maps/api/place/textsearch/json?query=%s&location=%s&fields=name,formatted_address,opening_hours,price_level,rating&key=%s" % (query,location, api_key)
    elif location is not None and radius is not None:
     url="https://maps.googleapis.com/maps/api/place/textsearch/json?query=%s&location=%s&radius=%s&fields=name,formatted_address,opening_hours,price_level,rating&key=%s" % (query,location,radius, api_key)

----Snip-----

Answer 1

我认为这段代码可以解决您的问题：

base_url = 'https://maps.googleapis.com/maps/api/place/textsearch/json?'
params = {
    'key': 'api_key', 
    'fields':'name,formatted_address,opening_hours,price_level,rating',
    'query' : query
}

if location is not None:
    params['location'] = location 
if radius is not None:
    params['radius'] = radius
    url = base_url + urllib.urlencode(params)

改善Google API调用

1 个答案: