Question

这是一个小的C程序，用于测试客户端和服务器程序，以便客户端向客户端发送一个整数。服务器将数字乘以10，然后将整数* 10返回给客户端。将整数写入FIFO时。到目前为止，这是我的代码：

#include <sys/stat.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <errno.h>
#include <fcntl.h>

main (void)
{
  int fda;      
  int fdb;      
  int number;
  int outputnumber;



  if((fda=open("FIFO_to_server", O_WRONLY))<0)
       printf("cant open fifo to write");

  if((fdb=open("FIFO_to_client", O_RDONLY))<0)
       printf("cant open fifo to read");

   printf("Client: Please enter an integer: ");
   scanf("%d", &number);


   write(fda, number, sizeof(number));
   printf("\nClient: Got the number sent, now waiting for response ");
   read(fdb, outputnumber, sizeof(outputnumber));
   printf("\nClient: received from server %s", outputnumber);

   close(fda);
   close(fdb);

   printf ("\nall done!\n");

 }

编译后，我出现了一些错误：

-bash-3.2$ gcc clientHw.c -o client
 clientHw.c: In function `main':
 clientHw.c:36: warning: passing arg 2 of `write' makes pointer from integer 
 without a cast
 clientHw.c:38: warning: passing arg 2 of `read' makes pointer from integer 
 without a cast

Answer 1

您必须像这样传递变量的地址：

write(fda, &number, sizeof(number));
...
read(fdb, &outputnumber, sizeof(outputnumber));

C语言中的read（）和write（）有什么错误？

1 个答案: