Nifi，Json数据

Question

我有json输入数据

204

如果column_type = 93（日期时间） ：将值转换为：{ "type" : "insert", "timestamp" : 1536959101000, "binlog_filename" : "mysql-bin-changelog.234234", "binlog_position" : 223, "database" : "test", "table_name" : "demo", "table_id" : 138, "columns" : [ { "id" : 1, "name" : "id", "column_type" : 12, "value" : "IboECKV " }, { "id" : 2, "name" : "col2", "column_type" : 93, "value" : "Fri Sep 14 21:05:02 UTC 2018" }, { "id" : 3, "name" : "col3", "column_type" : 4, "value" : 10 }, { "id" : 4, "name" : "col4", "column_type" : 4, "value" : 0 }] }

因此， 输出目标是

yyyy-MM-dd HH:mm:ss.SSSZ

你知道如何解决这个问题吗？

非常感谢，

Answer 1

您可以使用ExecuteScript并利用Groovy来解析Json输入和日期并将其格式化为想要使用SimpleDateFormat格式化的格式。

一个简单的例子：

import java.text.SimpleDateFormat 
import java.util.Date
import groovy.json.JsonSlurper
import groovy.json.JsonOutput
import org.apache.commons.io.IOUtils
import java.nio.charset.StandardCharsets

flowFile = session.get()
if(!flowFile)return
def text = ''

session.read(flowFile, {inputStream ->
  text = IOUtils.toString(inputStream, StandardCharsets.UTF_8)
} as InputStreamCallback)

def jsonSlurper = new JsonSlurper()
def object = jsonSlurper.parseText(text)

def columnsSize = object.columns.size

0.upto(columnsSize - 1) {
    if (object.columns[it].column_type == 93 ) {
        oldDate = object.columns[it].value
        sdfmt2= new SimpleDateFormat('dd-M-yyyy')
        parsedDate = sdfmt2.parse(oldDate)
        object.columns[it].value = parsedDate
        output = JsonOutput.toJson(object)

        flowFile = session.write(flowFile, {outputStream ->
            outputStream.write(output.getBytes(StandardCharsets.UTF_8))
        } as OutputStreamCallback)
        session.transfer(flowFile, REL_SUCCESS)
    }
}