Question

我有一些类似这样的记录

barcode:123, event:ASSIGN, event_datetime 9/23/2018 10am

barcode:123, event:CLOSE, event_datetime 9/23/2018 11am

barcode:123, event:ASSIGN, event_datetime 9/30/2018 10am

barcode:123, event:CLOSE, event_datetime 9/30/2018 11am

我想将这4条记录合并为2条看起来像这样的记录：

barcode:123, event:close, event_start_datetime 9/23/18 10am event_end_datetime 9/23/2018 11am

barcode:123, event:close, event_start_datetime 9/30/2018 10am event_end_datetime 9/30/2018 11am

我尝试了显而易见的MIN/MAX组合，但是由于所有其他列都是相同的数据（基本上，它们看起来像是重复的，除了一个列），因此它将使用最小/最大组合合并为一列。

我正在考虑使用rank()进行操作，但这听起来似乎变得非常复杂，我可以寻求帮助。

Answer 1

不是最优雅的答案，请尝试以下

select barcode, last_event_act, max(max_event_start), max(max_event_end) , event_datetime from 
(
select barcode, last_event_act, 
max(event_end) over (partition by to_char(event_end, 'mm/dd/YYYY')) max_event_end, 
max(event_start) over (partition by to_char(event_start, 'mm/dd/YYYY')) max_event_start, event_datetime
from 
(
select  barcode, last_value(EVENT) OVER (PARTITION BY to_char(EVENT_DATETIME, 'mm/dd/YYYY') ) as last_event_act, 
case 
    when event = 'CLOSE' then event_datetime 
    END 
 as event_end, 
 case 
     when event = 'ASSIGN' then event_datetime 
     END 
as event_start , max(to_char(event_datetime, 'mm/dd/yyyy')) over (partition by to_char(event_datetime, 'mm/dd/YYYY')) as event_datetime from barc
)
    )
    group by barcode, last_event_act, event_datetime

合并记录，每一列除一列外均具有相同的数据

1 个答案: