Question

我有一个哈希数组：

  records = [
    {
      ID: 'BOATY',
      Name: 'McBoatface, Boaty'
    },
    {
      ID: 'TRAINY',
      Name: 'McTrainface, Trainy'
    }
  ]

我正在尝试将它们组合成一个字符串数组：

["ID,BOATY","Name,McBoatface, Boaty","ID,TRAINY","Name,McTrainface, Trainy"]

这似乎什么也没做：

irb> records.collect{|r| r.each{|k,v| "\"#{k},#{v}\"" }}
#=> [{:ID=>"BOATY", :Name=>"McBoatface, Boaty"}, {:ID=>"TRAINY", :Name=>"McTrainface, Trainy"}]

**编辑**

格式化（即["Key0,Value0","Key1,Value1",...]才能匹配供应商的界面。

** / edit **

我想念什么？

Answer 1

records.flat_map(&:to_a).map { |a| a.join(',') }
#=> ["ID,BOATY", "Name,McBoatface, Boaty", "ID,TRAINY", "Name,McTrainface, Trainy"]

Answer 2

records = [
  {
    ID: 'BOATY',
    Name: 'McBoatface, Boaty'
  },
  {
    ID: 'TRAINY',
    Name: 'McTrainface, Trainy'
  }
]


# strait forward code
result= []
records.each do |hash|
  hash.each do |key, value|
    result<< key.to_s
    result<< value
  end
end
puts result.inspect

# a rubyish way (probably less efficient, I've not done the benchmark)
puts records.map(&:to_a).flatten.map(&:to_s).inspect

Answer 3

希望有帮助。

li = []
records.each do |rec|
    rec.each do |k,v|
      li << "#{k.to_s},#{v.to_s}".to_s
    end
end

print li

[“ ID，BOATY”，“名称，McBoatface，Boaty”，“ ID，训练”，“名称，McTrainface，训练”]

Answer 4

您确定要这样做吗？

签出Marshal。或JSON。

您甚至可以使用Hash#inspect和eval来做到这一点：

serialized_hashes = records.map(&:inspect) # ["{ID: 'Boaty'...", ...]
unserialized = serialized_hashes.map { |s| eval(s) }

序列化哈希数组

4 个答案: