Question

我有一个for循环语句，我想按顺序打印列表或数组中的所有信息。

所需的输出：

revised_grand_average

不幸的是，这是我收到的输出：

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    <div class="props">
      <div class="prop-item">Lorem ipsum</div>
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      <div class="prop-item">Lorem ipsum</div>
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      <div class="prop-item"> consectetur adipisicing elit. Voluptatum f</div>
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      <div class="prop-item">ugit magnam at, beatae ducimus, maiores, voluptas minus cumque quos est officiis a. Alias distinctio optio odio maxime nihil, delenit</div>

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    <div class="props">
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      <div class="prop-item">Lorem ipsum</div>
      <div class="prop-item">dolor sit amet,</div>
      <div class="prop-item"> consectetur adipisicing elit. Voluptatum f</div>
      <div class="prop-item">Lorem ipsum</div>
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它似乎遍历第三个数组。我认为嵌套循环设置不正确。

BUS: 1 JBUS: 12 ICKT: 1 
IBUS: 3 JBUS: 12 ICKT: 1 
IBUS: 4 JBUS: 16 ICKT: 1 
IBUS: 5 JBUS: 12 ICKT: 1 
IBUS: 1 JBUS: 14 ICKT: 2 
IBUS: 2 JBUS: 11 ICKT: 1

Answer 1

我认为该错误是由于嵌套循环引起的。这应该起作用：

FROM_BUS=[1,3,4,5,1,2]
TO_BUS=[12,12,16,12,14,11]
CKT=[1,1,1,1,2,1]


for f,t,c in zip(FROM_BUS, TO_BUS, CKT):
    print('IBUS: ' + str(f) + ' JBUS: ' + str(t) + ' ICKT: ' + str(c))

Answer 2

使用numpy的另一种方法

import numpy as np
FROM_BUS=[1,3,4,5,1,2]
TO_BUS=[12,12,16,12,14,11]
CKT=[1,1,1,1,2,1]
a=np.array([FROM_BUS,TO_BUS,CKT])
a=a.transpose()
for i in a:
    print('IBUS: {} JBUS: {} ICKT: {}'.format(*i))

输出：

IBUS: 1 JBUS: 12 ICKT: 1
IBUS: 3 JBUS: 12 ICKT: 1
IBUS: 4 JBUS: 16 ICKT: 1
IBUS: 5 JBUS: 12 ICKT: 1
IBUS: 1 JBUS: 14 ICKT: 2
IBUS: 2 JBUS: 11 ICKT: 1

如何修复循环输出语句？

2 个答案: