Question

我正在创建搜索功能。用户将在其中输入名称和城市。结果应显示为：应显示该城市可用的名称。 view.py

def search(request):
    if request.method == 'GET':
        srch = request.GET['srh']
        srch1 = request.GET['srh1']
        if srch:
            match = demo.objects.filter(Q(name__icontains=srch))
            if srch1 in match:
                match2 = demo.objects.filter(Q(city__icontains=srch1))
                if match2:
                    return render(request, 'listing-search.html', {'sr':match2})
                else:
                    print('no result found')
        else:
            return HttpResponseRedirect('')
    return render(request, 'listing-search.html')

模板

<form action="search/" method="get">
                    <div class="input-group input-group-1">
                      <span class="input-group-addon" id="basic-addon1">Find</span>
                      <input type="text" name= "srh" class="form-control" placeholder="Business Name Type Karo" aria-describedby="basic-addon1" list="find">

                    </div>
                    <div class="input-group input-group-2">
                      <span class="input-group-addon" id="basic-addon2">Location</span>
                      <input type="text" name="srh1" class="form-control" placeholder="Ex: Shahabad" aria-describedby="basic-addon2" list="suggest-location">

                    </div>
<button class="btn btn-default" type="submit"><i class="fa fa-search" style="font-size: 25px"></i></button>
                    <div class="fix"></div>
                  </form>

Models.py

class demo(models.Model):
    name = models.CharField(max_length=100)
    city = models.CharField(max_length=100, null=True,)

    def __str__(self):
        return self.name

Answer 1

代替此：

srch = request.GET['srh']
srch1 = request.GET['srh1']

使用此：

 srch = request.GET.get('srh')
 srch1 = request.GET.get('srh1')

Django python搜索结果问题

1 个答案: